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Xuekun October 29, 2015 19:10

Static Pressure Question
 
Hello,

I am modelling a laminar incompressible flow in the S pipe. The inlet velocity is quite small, generating Re=500, pressure outlet = 1 atm. Initial condition is P=1 atm. Why the static pressure is larger at the inlet than the outlet? Is this because the velocity at inlet is lower than outlet so Bernoulli's equation calculated a larger static pressure? Is my understanding correct?


The pressures I defined in the beginning is the static pressure or total pressure?


I need your help ! Thanks !

[IMG]http://s22.postimg.org/a2u8rer4t/QQ_20151029233830.jpg[/IMG]

[IMG]http://s22.postimg.org/7mx0rayfx/QQ_20151030000457.jpg[/IMG]

Sarang V October 30, 2015 15:04

If you are specifying velocity at the inlet and a static pressure at the outlet then then I would expect the static pressure to be high to drive the flow through the outlet.

Xuekun October 30, 2015 16:25

Quote:

Originally Posted by Sarang V (Post 571081)
If you are specifying velocity at the inlet and a static pressure at the outlet then then I would expect the static pressure to be high to drive the flow through the outlet.

Hi, thanks a lot for your reply. I just wander how the solver calculate the static pressure higher at inlet than outlet since I define the initial condition is 1 atm, same as outlet. Is this 1 atm the static or total pressure?

Sarang V November 2, 2015 10:49

As you said it is just an initial condition. Your initial conditions gets washed way as your simulation progresses. Initial conditions should not affect your end solution for a continuous flow problem (You might get convergence issues if they are set really bad).

fluid23 November 2, 2015 17:24

Quote:

Originally Posted by Xuekun (Post 571094)
Hi, thanks a lot for your reply. I just wander how the solver calculate the static pressure higher at inlet than outlet since I define the initial condition is 1 atm, same as outlet. Is this 1 atm the static or total pressure?

you must have a pressure gradient to have velocity (i.e. flow).


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