[dannygpx]

The case is flow into the two parallel plates (Top and Bottom).
The plate temperature is 500K (Fixed wall temperature).
Flow into temperature is 300K (Ambient temperature is 300K).

Assume：
1. Steady
2. Incompressible flow
3. Uniform flow
4. No heat source

u = ( + )

= 1.225 kg / m^3

u = 2 m / s ( x component velocity )

v = 0 m / s ( y component velocity )

c = 1006.43 J / kg * K

[lcarasik]

Originally Posted by dannygpx

The case is flow into the two parallel plates (Top and Bottom).
The plate temperature is 500K (Fixed wall temperature).
Flow into temperature is 300K (Ambient temperature is 300K).

Assume：
1. Steady
2. Incompressible flow
3. Uniform flow
4. No heat source

u = ( + )

= 1.225 kg / m^3

u = 2 m / s ( x component velocity )

v = 0 m / s ( y component velocity )

c = 1006.43 J / kg * K

What have you attempted so far? All you have shown what looks to be is a problem statement.

[dannygpx]

Originally Posted by lcarasik

What have you attempted so far? All you have shown what looks to be is a problem statement.

I was used FVM to calculate.

Assume：
length = 0.001 m
width = 0.001 m
u = 2 m / s
= 1.225 kg / m^3
k = 0.0242 W / m*K
x = y = 0.001/2 = 0.0005 m
Top and bottom are 300K.
Flow into temperature is 100K (Ambient temperature is 100K).

Temperature distribution：
300 300 300 300
100 86.7327 82.346 86.8175
100 90.4783 89.4623 96.7346
300 300 300 300

The temperature distribution is use MATLAB to solve.
Code：
u = 2; dx = 0.005; a = 0.0242/(1.225*1006.43);
A = [2*u*dx-6*a a-u*dx 0 a 0 0;a-u*dx 2*u*dx-5*a a-u*dx 0 a 0;0 a-u*dx 2*u*dx-6*a 0 0 a;a 0 0 2*u*dx-6*a a-u*dx 0;0 a 0 a-u*dx 2*u*dx-5*a a-u*dx;0 0 0 0 2*a-u*dx 2*u*dx-6*a];
B = [100*u*dx-800*a;-600*a;100*u*dx-200*a;100*u*dx-800*a;-600*a;100*u*dx-800*a];
C = A\B

C =

90.4783
89.4623
96.7346
86.7327
82.3460
86.8175