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3D velocity data from 2D data

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Old   January 23, 2019, 04:16
Default 3D velocity data from 2D data
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ssa
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Hi,

I have a time series velocity data from wind tunnel in 2d. I have the 'u' component and 'w' component.

Is there some way I could calculate the third velocity component 'v' from these data.

Thanks,
ssa
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Old   January 23, 2019, 04:23
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Originally Posted by ssa_cfd View Post
Hi,

I have a time series velocity data from wind tunnel in 2d. I have the 'u' component and 'w' component.

Is there some way I could calculate the third velocity component 'v' from these data.

Thanks,
ssa

No... the continuity equation can address a relation but also assuming you have an incompressible flow, the divergence-free constraint writes


dv/dy = -(du/dx+dw/dz)


you see that you need to measure directly the data of the third components.
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Old   January 23, 2019, 04:28
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Hi, Thanks for the quick reply.

One more question.
I am in need of calculating reynolds stress tensor for my simulation.

so with u and w, I could calculate only three tensor components and I need the remaining three. Is there some way to do it.?
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Old   January 23, 2019, 04:35
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Originally Posted by ssa_cfd View Post
Hi, Thanks for the quick reply.

One more question.
I am in need of calculating reynolds stress tensor for my simulation.

so with u and w, I could calculate only three tensor components and I need the remaining three. Is there some way to do it.?



No, unfortunately you do not have a real 2d problem but a 3d flow with only two known velocity components...
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Old   January 24, 2019, 12:30
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Someone else will be able to correct me if I am wrong. I have only recently gotten into turbulent flows, etc. But from what I understand, if you consider a flow around an airfoil for instance and if you want to use the experimental data for a simulation, the Reynolds stress terms in the spanwise direction would be zero on account of spanwise homogenity.

If this is what you need, you could probably do it without the third dimension, provided you have data in the right directions.
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Old   January 24, 2019, 13:04
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the Reynolds stress terms in the spanwise direction would be zero on account of spanwise homogenity.

Spanwise homogenity just means d/dy(stuff) = 0, it doesn't necessarily mean that stuff (v') is zero.
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