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-   -   tke(f)=E(f) ??? (https://www.cfd-online.com/Forums/main/218513-tke-f-e-f.html)

lucamirtanini June 23, 2019 15:29

tke(f)=E(f) ???
 
Hi,
In a lot of book about turbulence (Pope, Reynolds, Tenneke and Lumley...) there is written this formula that define the spectrum:
\frac{1}{2}(\overline{u^{2}}+\overline{v^{2}}+\overline{w^{2}})=\intE(k)dk (1)

Of course, it could be written as well:
\frac{1}{2}(\overline{u^{2}}+\overline{v^{2}}+\overline{w^{2}})=\intE(f)df (2)

Now, if the (2) is true, starting from the time history of the specific turbulent kinetic energy (let's call it tke(t)), I can do the fft of it

fft(tke(t))= tke(f) (3)

and the tke(f) should be equal to E(f).

Unfortunately, when I apply the formula (2) doing
\frac{1}{2}(\overline{u^{2}}+\overline{v^{2}}+\overline{w^{2}})=\inttke(f)df
this formula is not verified (there are a lot of magnitude order of differences).

So I am wandering if I am doing mistake in the theory and which are my mistakes. I hope you can help me

bhigahAshish June 25, 2019 09:56

I think that (1) and (2) are correct.
But I notice some problem with the third. Firt of all you need to do a Fourier transform and not a fft which are very different things.
Unfortunately, I am not sure that tke(f) and E(f) are the same thing.


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