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Simulating supersonic flow in a spinning nozzle |
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April 25, 2022, 07:39 |
Simulating supersonic flow in a spinning nozzle
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#1 |
Member
Syed Wajeeh
Join Date: Mar 2022
Posts: 56
Rep Power: 4 |
Hello all.
I am new to ANSYS fluent and I am simulating internal compressible flow in a nozzle which is spinning*about its axis. I have run the simple simulations which work fine but when I give rotations to the wall or just to the whole solid body, the simulations get complete but I am unable to get the desired result as my streamlines and flow both are still straight. Can someone please help me to model and analyze this properly? I will be very thankful WhatsApp Image 2022-04-25 at 3.09.46 PM.jpeg |
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April 25, 2022, 12:04 |
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#2 |
Senior Member
Join Date: Jul 2009
Posts: 351
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Are you running inviscid? Or, if you are running viscous do you have the correct BC set at the solid wall - it won't be zero velocity for the flow.
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April 25, 2022, 16:03 |
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#3 |
Member
Syed Wajeeh
Join Date: Mar 2022
Posts: 56
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Hello agd. My BCs are inlet pressure = 5.099MPa, Outlet Pressure = 101325 Pa. Left and rights faces are Symmetry-1 and Symmetry-2 and wall is moving wall with rotational velocity of 62.83 rad/s, axis origin at the start of inlet and in the direction of X.
Please tell me if I am wrong at some step. Or if there is any other method of applying spin to the nozzle. Thanks in advance |
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April 25, 2022, 16:05 |
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#4 |
Member
Syed Wajeeh
Join Date: Mar 2022
Posts: 56
Rep Power: 4 |
I am running k-w SST.
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April 25, 2022, 21:24 |
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#5 |
Senior Member
Lucky
Join Date: Apr 2011
Location: Orlando, FL USA
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You should be using periodic boundary conditions and not symmetry conditions. Symmetry conditions will make the flow always straight.
With that being said, I have no clue how it even converged. |
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April 26, 2022, 04:52 |
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#6 |
Member
Syed Wajeeh
Join Date: Mar 2022
Posts: 56
Rep Power: 4 |
Lucky can you help me in understanding why should I be using periodic conditions and how can I set up these in my problem in ANSYS fluent? I will be very thankful to you
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April 26, 2022, 10:16 |
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#7 |
Senior Member
Lucky
Join Date: Apr 2011
Location: Orlando, FL USA
Posts: 5,674
Rep Power: 65 |
Because the velocity normal to the symmetry plane must be 0 or it wouldn't be symmetry. That is, no flow vector can cross the symmetry plane. And that means that the flow will always be parallel to the plane.
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April 26, 2022, 19:38 |
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#8 |
Member
Syed Wajeeh
Join Date: Mar 2022
Posts: 56
Rep Power: 4 |
Got it. Thanks a ton Mate. Stay blessed
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