CFD Online Discussion Forums

CFD Online Discussion Forums (https://www.cfd-online.com/Forums/)
-   Main CFD Forum (https://www.cfd-online.com/Forums/main/)
-   -   2D version of mass co-ordinate (https://www.cfd-online.com/Forums/main/251419-2d-version-mass-co-ordinate.html)

hunt_mat August 15, 2023 12:55

2D version of mass co-ordinate
 
It is possible to simplify the Euler equations by introducing a new set of Lagrangian co-ordinates.
(t,x)\mapsto (t',h), by t=t' and h is defined by:
\frac{\partial h}{\partial x}=\rho
This method has the nice property of fixing the amount of mass in an interval(this can be demonstrated by integrating the definition of h, and using the Lagrangian conservation of mass.

My question is this: Is there something similar for 2D?

FMDenaro August 15, 2023 16:47

Quote:

Originally Posted by hunt_mat (Post 855308)
It is possible to simplify the Euler equations by introducing a new set of Lagrangian co-ordinates.
(t,x)\mapsto (t',h), by t=t' and h is defined by:
\frac{\partial h}{\partial x}=\rho
This method has the nice property of fixing the amount of mass in an interval(this can be demonstrated by integrating the definition of h, and using the Lagrangian conservation of mass.

My question is this: Is there something similar for 2D?




http://depts.washington.edu/clawpack...system_2d.html

LuckyTran August 15, 2023 20:06

Recognize that x and h can be generalized to vectors and that d/dx is actually a divergence operator. In other words, it works in n-d! See Noether's second theorem.

hunt_mat August 16, 2023 05:15

Quote:

Originally Posted by LuckyTran (Post 855332)
Recognize that x and h can be generalized to vectors and that d/dx is actually a divergence operator. In other words, it works in n-d! See Noether's second theorem.

I thought that it would be generalised from the fact that mass is conserved for the cells, the integral of the density would give the amount of mass in a particular direction.

LuckyTran August 16, 2023 07:18

You're literally assuming the premise when you say the question you are trying to ask is explained by itself

hunt_mat August 17, 2023 06:28

I think that there is an easy generalisation, you just have to use:
\frac{\partial a}{\partial x}=\rho,\quad \frac{\partial b}{\partial y}=\rho
Then this gives the following linear equations for the conservation of mass and momentum:
\frac{\partial\nu}{\partial t}=\frac{\partial u}{\partial a}+\frac{\partial v}{\partial b}
\frac{\partial\mathbf{u}}{\partial t}=-\nabla_{a,b}p
This transformation is good because it makes the convective terms disappear (like any lagrangian co-ordinate) but (hopefully) allows a fixed set of co-ordinates. like Eulerian co-ordinates.


All times are GMT -4. The time now is 09:44.