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September 14, 2002, 18:43 |
Non-dimensional k-w
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#1 |
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Hi all. I am trying to implement Wilcox's two equation k-w turbulence model, and am having a hard time with the non-dimensionalization of 'w'. What is the appropriate non-d parameter:
(1) w_inf = U_inf/L-inf (2) w_inf = (U_inf)**2/L-inf (3) w_inf = sqrt(U_inf**3 /(Nu_inf * L-inf)) Depending on the parameter used, the Reynolds number term appears in front of the Dissipation term. What is the physics behind determining which parameter to use? Is it a problem-based choice? My test cases would involve supersonic external flows. Thanks for all your input. |
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September 14, 2002, 18:46 |
Correction
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#2 |
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Oops! The second parameter should have been
(2) w_inf = U_inf/Nu_inf which gives the correct dimensions of 1/time for w. Thanks! |
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September 16, 2002, 09:36 |
Re: Non-dimensional k-w
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#3 |
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If you already have a k-eps model implemented, look at its non-d parameters. First of all, w=eps/k, so the non-dimensionalized form of k and eps will give you the appropriate form of w.
Sylvain |
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