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-   -   Weber Number (https://www.cfd-online.com/Forums/main/64747-weber-number.html)

Fabio May 22, 2009 05:01

Weber Number
 
Hi all, it shold a very simple question, but i have found different answers to that. In the Weber number i should use the density of the droplet or the continuous density? In my case i got liquid droplets injected in gas phase. Thx in advance.

senecal May 22, 2009 09:41

Hi Fabio,

The Weber number definition depends on what you are using it for. Are you using the Weber number to calculate another quantity, or in a model such as drop breakup?

Fabio May 22, 2009 10:31

Hi, i need to calculate this number to choose the proper breakup model.
Which of the twi density i got i need to put in the formula?

senecal May 22, 2009 10:36

Fabio,

Without seeing the code or knowing what the breakup models are, I would say it is probably gas density. You need to verify this though. Do you have any documentation for the code you are using (what code is it)?

Fabio May 22, 2009 11:10

Sorry, i was thinking that was only a matter of definition of the Weber number.
Anyway the code is FLUENT and docementation says that there are two breakup model TAB nad WAVE, for We\geq 100 the latest shall be used. Documentation also says that i should use continuous phase density but the result is very low We=0.4776.

senecal May 23, 2009 14:10

Hi Fabio,

What type of spray are you modeling?

Fabio May 23, 2009 16:36

I'm modeling a solid 3d cone spray of a liquid in an hot gas. Did you mean this?

senecal May 27, 2009 21:44

Fabio,

I was just wondering if this is a gasoline spray, Diesel spray, or some other type of spray. You mentioned that the Weber number that you calculated seems very low and so I just wanted to see if that makes sense. For example, the Weber numbers for Diesel sprays are typically higher than gasoline sprays.

Fabio May 28, 2009 02:43

Sorry, it isn't an engine injection i'm studing an SCR the fluid density is a bit more of water density 1084-1092 kg/m^3.

prasad.ichal May 28, 2009 08:35

How about using both models and checking how close you go to the desired results; experimental results if available? Although it is a very non-technical answer, I couldn't help replying your question.

Fabio May 28, 2009 08:47

Unfortunately i haven't experimantal data to match, i have to study the trajectories of the injected particle with diffent duct geometries. So i need one right model to use for the different simulations to match the results. i hope to have expressed well which is the point of the situaton.

anon_n May 28, 2009 08:50

continuous phase is in this case the gas phase

Fabio May 28, 2009 08:53

So the definition in the manual is right there isn't any ambigous definition?

prasad.ichal May 28, 2009 09:07

The spray for SCR requires high pressure injection involving higher velocities and hence higher inertial forces. Certainly it will call for the use of wave breakup model. You will have to choose the model constants carefully.

Fabio May 28, 2009 09:43

As documentation says Weber number guide the choice of the breakup model, for that reason i have asked here the right density to use, with the gas density as suggested on manual i got a result much less than We=100 that indicates TAB as correct to use. I'm getting confused, injestion pressure is 600kPa.

triple_r May 28, 2009 18:19

Hi,

I think the Weber number must be based on gas phase (continous phase) as you can find in the papers which classify mechanisms of drop breakup (e.g. Liu and Reitz, "An analysis of the distortion and breakup mechanisms of high speed liquid drops", 1997).

In these papers you can find the classification of the drop breakup mechanisms, and see that Kelvin-Helmholtz instability occurs when gas Weber number goes over 80, and Taylor Analogy Breakup is not good when this instability is the dominant mechanism (as FLUENT suggests We > 100).

Fabio May 29, 2009 05:03

This point is clear, i have used TAB model because We<100 but i would like to know i have computed this in the proper way using gas phase density.
Thanks for the help.


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