# Question in CFD

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 August 6, 2009, 14:08 Question in CFD #1 shosho Guest   Posts: n/a Hi freinds I have this equation + + - (+ )= 0 which comes from continuty equation + + = 0 and the radial coordinate transformation = = my question now how I can get the first equation? I mean what the steps to get it by using the continuty equ and transformation? Kind Regards Shosho

 August 6, 2009, 23:02 #2 New Member   Ananda Himansu Join Date: Apr 2009 Location: Cleveland, Ohio, USA Posts: 17 Rep Power: 10 I will refer to your equations as (1), (2) and (3). You are transforming independent coordinates from (r, z) to (xi, zeta), where xi is given by your eqn (3) and zeta = z. The dependents u and w were previously functions of r & z, and are now functions of xi & zeta. R1 and R2 (and also R1-R2) are functions of z, and thus of zeta, but are independent of r and of xi. Recognize that when transforming your original continuity eqn (2), you must now treat w as a function of xi and zeta, but the derivative is with respect to z while holding r constant. Apply the chain rule for this derivative (dw/dz = dw/dzeta*dzeta/dz + dw/dxi*dxi/dz) and you get your transformed continuity eqn (1), noting that all occurrences of z in (1) are really zeta and that the derivative dw/dzeta is now holding xi constant (not r). The first two terms in (2) get trivially transformed to the first two terms of (1). Last edited by Ananda Himansu; August 6, 2009 at 23:07. Reason: distinguished between dw/dz in eqns (1) and (2)

 August 7, 2009, 09:58 #3 shosho Guest   Posts: n/a Thanks Ananda Himansu Dear friends, one of my friends send me this solution but unfortunatlly i didn't understand it . Can you please One explain it to me?. 1. \xi = \xi(r, R_1, R_2) 2. R_1 = R_1(z,t) and R_2 = R_2(z,t), hence (3. & 4. hold): 3. u(r , z , t) = u(\xi , z , t), 4. w(r , z , t) = w(\xi , z , t) so that (5. & 6. hold): 5. u_r = u_{\xi} * \xi_r (from 3.) 6. w_z = w_{\xi} * \xi_z + w_z (from 4.) formulas 5. and 6. should answer your question! Kind Regards Shosho

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