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shuo September 28, 2009 20:51

isothermal B.C.
 
I have a question regarding the implementation of isothermal no slip wall boundary condition. I am using ghost points at (i+1) to generate a wall at i + 1/2.

u_i = - u_i+1
v_i = - v_i+1

rho_i = rho_i+1
P_i = P_i+1

T_i = ?

Cheers
S.

preetam October 2, 2009 11:31

I guess it will be a constant and specify a value for your temperature.

For example you can use Ti=60F

praveen October 2, 2009 13:03

If you follow your logic for other variables, you should choose T_(i+1) so that

(T_i + T_(i+1))/2 = Twall

You cannot of course specify density, pressure and temperature. You must choose only two of them, perhaps, pressure and temperature.


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