cell face side length.
I ne
cell face side length.
I need to access the length of cell face in x or z direction. The cells are have hexagonal shape. I thought to use sqrt(magSf) but this will be correction only if dx=dz. Do you know any way to do this. Thansk. Best regards, Maka. 
I thought of the following but
I thought of the following but it is only valid if mesh resolution in z direction (dz) is uniform.
const fvPatchScalarField& vsfp = vsf.boundaryField()[patchI]; // first cell scalar cf1 = vsfp[xPatchFaceLabel(0,k)].patch().Cf(); scalar A1 = vsfp[xPatchFaceLabel(0,k)].patch().magSf(); // last cell scalar cfn = vsfp[xPatchFaceLabel(nx()1,k)].patch().Cf(); scalar An = vsfp[xPatchFaceLabel(nx()1,k)].patch().magSf(); // Assuming constant resolution in z direction and cell centered node. scalar dz = (A1+An)/(2*(cf1+cfn)); scalar dx1 = A1/dz; scalar dxn = A2/dz; is there a general solution, like using bounding box on the cell? Thanks. 
scalar dxn = An/dz; That was a
scalar dxn = An/dz; That was a correction.

The above is wrong, the correc
The above is wrong, the correct way is to get: faces from the patch and get the edges. I can do that but the problem is that I can not find the function that gives the faceList from polyPatch for example
vsfp.patch().*?* will give faceList of the patch ? 
The solution is:
vsfp.patch()
The solution is:
vsfp.patch().patch().localFaces()[face_label].edges()[edge_label].centre(vsfp.pa tch().patch().localPoints()) 
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