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Solid-Solid thermal resistance layer thickness

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Old   November 12, 2018, 07:41
Default Solid-Solid thermal resistance layer thickness
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Adam
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It looks like the correct way to handle the interface between two solid regions is with the compressible::turbulentTemperatureCoupledBaffleMix ed type BCs, as seen in the multiRegionHeater tutorial and several posts here but I still have a question about their implementation.

In the extended code guide/examples, I see:
Code:
Usage
Property	Description	Required	Default value
Tnbr	name of the field	no	T
thicknessLayers	list of thicknesses per layer [m]	no	
kappaLayers	list of thermal conductivities per layer [W/m/K]	no	
kappaMethod	inherited from temperatureCoupledBase	inherited	
kappa	inherited from temperatureCoupledBase	inherited
My boundary condition is the following

-K*(dT/dr) evaluated at the surface of the particle = (T_surface-T_matrix)/Resistance

Are the thicknessLayers and kappaLayers themselves important? Or are they just used to calculate the coupling between the two surfaces? For example, if I have 10 µm radius particles and I know the inter-facial resistance with the matrix is 0.1 (m²*K)/W is there a difference between the two cases.

Case A
thicknessLayers (1e-6) [m]
kappaLayers (1e-5) [W/m/K]

Case B
thicknessLayers (1e-7) [m]
kappaLayers (1e-6) [W/m/K]
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Old   November 13, 2018, 05:25
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Should be the same.
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Old   November 14, 2018, 23:56
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Quote:
Originally Posted by TobM View Post
Should be the same.
I think you're right. There was no difference between two simulations I ran with

Code:
thicknessLayers	(1);
kappaLayers	    (1e2);
and
Code:
thicknessLayers	(1e-9);
kappaLayers	    (1e-7);
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