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Boolean function to mimic basic Octave function

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Old   September 2, 2013, 07:22
Default Boolean function to mimic basic Octave function
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Hi all,

I am trying to do some simple thing that takes no more than 15 seconds to do in Octave but it is taking me some hours in c++.

Regarding dynamic mesh, when selecting points to move, there is already a function in OF that picks the boundary points and everything goes well.

It happens that I just want some of the boundary points to I would like to get something like this:

I have a pointField XYZ;

I would like to compare the pointField.component(0) with a scalar 0 (or a scalarFeld e.g. pointField.component(0) > 0) and return a scalarField with 1 if it is true and 0 if it is false.

I have tried something like this:

scalarField test = bool ( pointField.component(0) > vector::zero.component(0));

but it tells me I can't use the > operator..

I could get a similar result with a loop, but I am trying to avoid it..

any hints?

Thank you

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Old   September 2, 2013, 09:23
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Something along the lines of:

scalarField test = pos ( pointField.component(0) - vector::zero.component(0) > 0);
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Old   September 2, 2013, 11:49
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thanks, that was it!
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