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phi == pEqn.flux() rhoSimpleFoam

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Old   July 9, 2015, 11:10
Question phi == pEqn.flux() rhoSimpleFoam
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Does anyone know why for the transonic case in rhoSimpleFoam the flux is calculated as:

phi == pEqn.flux(); ?

If transonic is turned off, then the flux is calculated in the 'normal' way, i.e. first calculting the flux without the contribution of the pressure gradient:

phi = fvc::interpolate(rho)*(fvc::interpolate(U) & mesh.Sf() )

And after the calulation of the pressure, the old flux value gets corrected using the new pressure:

phi -= pEqn.flux();

So I do not understand why the flux in the transonic case is not calculated as:

phi == fvc::interpolate(rho)*(fvc::interpolate(U) & mesh.Sf() ) - pEqn.flux()

as well.

I hope somebody can help me with this.
Thank you in advance!
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flux, peqn, phi, rhosimplefoam, transonic

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