[vkoppejan]

Hi Everyone,

I work a lot with vectorList and scalarList and I would like to replace them by their dimensioned version, so List<dimensionedVector> and List<dimensionedScalar>.

At the moment I declare the lists in the headerfile but this is a problem for the dimensioned versions.

Declaring:

List<dimensionedVector>

uses the constructor below

template<class Type>
Foam::dimensioned<Type>::dimensioned
()
:
    name_("undefined"),
    dimensions_(dimless),
    value_(pTraits<Type>::zero)
{}

How can I make it use one of the other constructors, preferably

template<class Type>
Foam::dimensioned<Type>::dimensioned
(
    const word& name,
    const dimensionSet& dimSet,
    const Type t
)
:
    name_(name),
    dimensions_(dimSet),
    value_(t)
{}

Thanks in advance,

Victor

[Diro7]

Hi Victor!

I guess I'm experiencing the same kind of trouble, as I'm not able to declare a List<dimensionedScalar> without having it initialized with the null constructor, which then prevents me to assign to the list elements with different dimensions.

After all this time, did you manage to solve your problem?

Andrea

[vkoppejan]

Hi, sorry for the late reply. I didn't find a solution.

[gaza]

Originally Posted by Diro7

Hi Victor!

I guess I'm experiencing the same kind of trouble, as I'm not able to declare a List<dimensionedScalar> without having it initialized with the null constructor, which then prevents me to assign to the list elements with different dimensions.

After all this time, did you manage to solve your problem?

Andrea

I do not know if it helps but I create the list of 10 dimensioned scalars
with value 0 like this in the constructor

    myListDS_{List<dimensionedScalar>(10, dimensionedScalar(dimLength, 0).value())}

It compiles. However, if I do not have

value()

method I get the error of different dimensions in OF case.