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The meanings of diag( ), source( ), psi( ) 

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March 16, 2011, 06:25 
The meanings of diag( ), source( ), psi( )

#1 
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Xuan Cai
Join Date: Mar 2011
Location: Karlsruhe, Germany
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I am using the solver"porousSimpleFoam" to run simulations on a domain including porous media.
In the UEqn.H, the momentum equation is implemented as follows: // Construct the Momentum equation tmp<fvVectorMatrix> UEqn ( fvm::div(phi, U) + turbulence>divDevReff(U) ); Then in the file: /src/finiteVolume/cfdTools/general/porousMedia/porousZone.C we have the following code: ================================================== ========== scalarField& Udiag = UEqn.diag(); vectorField& Usource = UEqn.source(); const vectorField& U = UEqn.psi(); ================================================== ========== Does anyone know the exact meanings of UEqn.diag(), UEqn.source(), UEqn.psi() in details, e.g. what do these functions return? Or could anyone give some hints about that? Thank you very much 

March 16, 2011, 09:46 

#2 
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Alton Luder III
Join Date: Oct 2009
Location: Michigan
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See the source code documentation.
Here is the list of all members of fvMatrix since diag() is inheirited http://foam.sourceforge.net/docs/cpp...ixmembers.php 

March 16, 2011, 12:08 

#3  
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Santiago Marquez Damian
Join Date: Aug 2009
Location: Santa Fe, Santa Fe, Argentina
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Hi,
Quote:
Regards.
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March 17, 2011, 04:56 

#4  
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Xuan Cai
Join Date: Mar 2011
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Quote:
Hi Santiago. Thanks for your reply. In the openfoamwiki, I learn that disretization of PDE leads to an algebraic equation in the following form: AΨ = B So does UEqn.diag() mean the diagonal of A, UEqn.source() mean B and UEqn.psi() mean Ψ ? 

September 19, 2013, 13:53 

#5  
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Hassan
Join Date: Oct 2012
Location: Iran
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Quote:
Please attention to this post. ? Regards, Hassan 

June 17, 2015, 14:13 

#6  
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Dongyue Li
Join Date: Jun 2012
Location: Beijing, China
Posts: 775
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Quote:
For example, if you are discritizing velocity, u will have an symmetry matrix. After discritization, u will have Ax = B, A will be symmetric, Then OpenFOAM will do: [A.diag()+A.offdiag()] x = B; A.diag() x = B  A.offdiag() x; For symmetric matrix, A.diag() will be the diagonal of A, A.offdiag() x will be the source of A. That means if your matrix equation is like this: A x = 0; U also have an source() term.
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