Scalar precision: float vs. double
 

Hi

I use scalars to solve a (simple closed form) quadratic equation. Nevertheless, they always give a 6 digits precision (a float). I tried to declare the scalars as doubleScalar instead of just scalar. However, the result is still in 6 digits. I made sure that the solution can be more precise http://www.mathsisfun.com/quadratic-...on-solver.html

This is probably an output related issue.
How are you printing out your results?


Greetings,
Felix

I use the following

Thanks for the tip. I guess it is an output issue. So using "cout" one can use:

Is there a possible way around for "Info" just for debugging sake. Anyway thanks a lot for quick answer.

Vielen Dank nochmal :D

There's a couple of precision options in the controlDict. One is for the time directory name, and the other is for the output. Can't remember what they are off-hand, but they should be easy to find.

Hi marupio

Thanks a lot, I found it: