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May 9, 2013, 04:16 
initial residual and final residual

#1 
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Maosong Cheng
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what is the definition of the initial residual and final residual, which can be used to decide convergence ? 

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May 15, 2013, 05:20 

#2 
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Anne Gerdes
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The initial residual is evaluated based on the current values of the field before solving an equation for a particular field . The final residual is evaluated after the solution of the equation is performed.
The intial residual is more important to decide whether a computation converges, or not. 

May 15, 2013, 08:23 

#3 
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Timo K.
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Hi Anne,
can you give some rule of thumbs for values, which should be achieved for the initial/final residual and how many iterations should be used for pEqn per cycle e.g. for a transient simulation with a standard PCG solver. Best Timo 

May 15, 2013, 08:29 

#4 
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Anne Gerdes
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Initial residual: e^4 or e^5 is a good result. Final residual has to be smaller (e^8).
I cannot answer your 2nd question. 

August 17, 2016, 15:45 

#5  
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Manm
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Quote:
Hi, based on this definition, I was curious as to why the final residual in one time step NOT equal to initial residual in NEXT time step? 

August 17, 2016, 15:55 

#6 
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Bruno Blais
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Assuming you are solving in steady state, it is because the equations are nonlinear.
If you solve the momentum equation for U, at the next iteration, P and phi will have been changed. Therefore, the initial residual will be different from the final residual of the last iteration. If you were to solve a linear equation, noncoupled with any other variables, in steadystate, then you would solve it in a single iteration... and therefore your "next initial" residual would be your last final one... 

August 17, 2016, 17:13 

#7  
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Manm
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Quote:
If I understand it right, Say : U =f(p,phi,t) where f is a complex function If t0 =0: During 1 st iteration, we start with a p0, phi0 and dt time step and get U1 =f(p0, phi0,dt) as well as p1, phi1 values. The corresponding final error/ residual is calculated from U1 and true U expected. Before 2nd iteration starts, a (say) U12 is calculated based on new available values: U12 =f(p1,phi1,dt) and this is used to calculate the initial error/ residual before the 2nd time step starts. and then we go on to calculate U2 =f(p1, phi1, dt+dt) and corresponding p2, phi2 and final error/ residual at the end of 2nd time step and so on.... 

August 18, 2016, 08:31 

#8  
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Bruno Blais
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Yup, That is exactly so.
OpenFOAM is a segregated solver, that is U, V, W, phi and P are solved segregated. This is why such a thing happen. There are block coupled solvers in foamextend, but those are still linear solver and don't implement a nonlinear newton method or something like that. Quote:


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