|March 27, 2014, 10:32||
second derivatives in the navier stokes equation
Join Date: Nov 2010
Posts: 14Rep Power: 8
I just have a quick question:
are the second derivatives in the navier stokes equation symmetric? In other words:
d/dx d/dy ux(x,y) = d/dy d/dx ux(x,y) ? where ux is the x-component of the fluid velocity.
Thanks for your response!
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