|
[Sponsors] | |||||
second derivatives in the navier stokes equation |
![]() |
|
|
LinkBack | Thread Tools | Search this Thread | Display Modes |
|
|
|
#1 |
|
New Member
Gregory
Join Date: Nov 2010
Location: Dresden
Posts: 14
Rep Power: 17 ![]() |
Dear all,
I just have a quick question: are the second derivatives in the navier stokes equation symmetric? In other words: d/dx d/dy ux(x,y) = d/dy d/dx ux(x,y) ? where ux is the x-component of the fluid velocity. Thanks for your response! |
|
|
|
|
|
![]() |
| Thread Tools | Search this Thread |
| Display Modes | |
|
|
Similar Threads
|
||||
| Thread | Thread Starter | Forum | Replies | Last Post |
| Adding a term to Navier Stokes Equation | ashtonJ | CFX | 9 | July 30, 2025 04:12 |
| NAvier Stokes and Newton's law coupling | archeoptyrx | Main CFD Forum | 10 | March 6, 2014 03:42 |
| Navier Stokes algorithm 2D abnormal behaviour | fighter20045 | Main CFD Forum | 0 | April 6, 2013 07:37 |
| Conservative form of Navier Stokes equation. | balkrishna | OpenFOAM Running, Solving & CFD | 2 | January 25, 2012 09:33 |
| coupling KE equation with navier stokes equation | prashant | FLUENT | 0 | March 7, 2008 08:05 |