slip boundary's equation.
 

Hi guys,

In inviscid flow, wall's boundary is slip. Lets take account of velocity: the equation of velocity in the slip boundary should be:




The reason is that: n_x=0.n_y=-1,u_y=0.

But in user guide it said:

I can understand the first sentence. Because u_y=0.

So how can I derive that the tangential vector is zeroGradient?

Thanks

hello
for incompressible fluid:
i think we could deduce "the tangential vector is zeroGradient" from equation of continuity .

Best Regards
xuhe

Could you elaborate it more? I want to know how can I get

Thanks.

may this help you !
 

look down the picture ！
is it clear ？

do you deal with twophase fluid ?



xuhe

cool, wonderful.

Yep, Im using solver on two-fluid model.

Thanks.:)

Your equations are not correct. v(y=0)=0 does mean dv/dy=0 per se (i.e. if v(y=1)=1). Therefore, your statement that du/dx=0 is not correct. A slip boundary is impermable (thus v=0) and stress-free (thus du/dy=0, for your sketch).

thank you very much!

:p

Oops, We should be more care about it. Yep, it should be du/dy=0 not du/dx=0.

Just because its stress free. so u(y=0) has no impact on u(y=1). So this du/dy=0. It makes sense.

Thanks.