|
[Sponsors] |
March 5, 2007, 09:11 |
I am about to simulate the "hi
|
#1 |
New Member
Holger Putz
Join Date: Mar 2009
Posts: 5
Rep Power: 17 |
I am about to simulate the "hidrostatic head" of a simple column (cylinder full of water).
the remaining equation to solve is actually dp/dz=rho*g (1) So, I added the gravity to the momentum equation and set u-vectors equal to zero. No inlet to the cylinder and no outlet. Just water. And I want to calculate the pressure difference between the top and the bottom of the cylinder. however the result is not matching the equation p(top)-p(bottom)=rho*g*h (2) and I dont have an explanation for that. Henry netioned in the board that the pressure p in simpleFoam is rho/p. If I take the equation into account, the calculated result is not matching eq.(2) anyway. Unfortunately, I dont know how to handle that situation in OpenFoam. What BC do I need for this job? Any help you can give would be very much appreciated. Regards, Holger |
|
March 6, 2007, 16:20 |
Hello Holger,
I am also hav
|
#2 |
Member
Shaun Cooper
Join Date: Mar 2009
Posts: 54
Rep Power: 17 |
Hello Holger,
I am also having problems with hydrostatic equilibrium. I would also like to know if someone has a solution for this problem. Shaun |
|
|
|
Similar Threads | ||||
Thread | Thread Starter | Forum | Replies | Last Post |
hydrostatic pressure | Amanda | FLUENT | 6 | April 20, 2016 11:00 |
Hydrostatic pressure(rho*g*h) | Pranesh | FloEFD, FloWorks & FloTHERM | 3 | October 17, 2008 06:18 |
hydrostatic pressure | attax | CFX | 0 | September 8, 2005 09:27 |
hydrostatic pressure | multiphase | FLUENT | 0 | May 18, 2003 15:16 |
Hydrostatic Pressure | Rhydar | CFX | 3 | March 6, 2002 09:54 |