Hi,
It seems that nobody ha
Hi,
It seems that nobody has read my question. I am posting this to bring it to attention. Can anyone answer it? Is there any implemented BC in OpenFOAM that can be used to treat implicitly a BC of third kind? Thanks for any help, Paulo 
mixedFvPatchField in the finit
mixedFvPatchField in the finiteVolume library?

I'll give it a shot.
k*nf &
I'll give it a shot.
k*nf & grad(T)_b = Cp*U_b*(T_bTo) k*nf & grad(T)_b = k*snGrad(T)_b k*snGrad(T)_b = k*(T_b  T_cell)/(nf & d) where d = X_boundaryFace  X_cellCentre Thus T_b = (k*T_cell/(nf & d)  Cp*U_b*To)/(k/(nf & d) Cp*U_b) Once you have the correct boundary value of T, snGrad(T) can be found without iteration. Of course you have to stick all this stuff inside the evaluate function of your custom boundary condition so it can be updated properly. See OpenFOAM1.3/src/finiteVolume/fields/fvPatchFields/basicFvPatchFields/fixedGradi ent/fixedGradientFvPatchField.C line 137140 for details. Is this what you wanted or am I competely missing the point? If so you will have to do a bit more explaining. (PS. I probably made some mistakes with the gradient signs) 
Dear Mattijs Janssens,
I ha
Dear Mattijs Janssens,
I had already checked the mixedFvPatchField because of its name. Due to your suggestion, I read the code again more carefully. From it, it seems that mixedFvPatchField should do the job for the BC: nf & grad(T) = A*(Tref  T) if I specify: refGrad = 0 refValue = Tref and calculate f at each boundary face of the patch by f = A/(A+1/d), where 1/d = patch().deltaCoeffs() and 0<f<1>0, as soon as the local A value is available. If it is constant (not my case), this has to be done only once at the beginning of computation. For a third order boundary condition that comes from flux conservation: k (nf & grad(T)) = h*(T  Tref) => A = h/k > 0 For a Danckwertz boundary condition: (nf & grad(T)) = (Cp/k)*(phi/magSf)*(TTref) => A =  (Cp/k)*(phi/magSf) > 0 because phi < 0 at an inlet boundary. I have not tried yet, but I will post if this solution works after trying. Does this seem correct to you? Thanks. 
A small mistake in the line:
A small mistake in the line:
f = A/(A+1/d), where 1/d = patch().deltaCoeffs() and 0<f<1 for A>0, in the previous post. The system did not produce correctly the text: 0<f<1 for A>0 both in the same line. 
All times are GMT 4. The time now is 11:26. 