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- - **Difference between oodles and "oodLagrangianFoam**
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Difference between oodles and "oodLagrangianFoamDear all:
I have made a solver of oodLagrangianFoam as icoFoam. Now everything is ok except there is some difference between the result of "oodles" and "oodLagrangianFoam" when I only compute the flowfield. The difference is as the below lines: oodLagrangianFoam Starting time loop Reading/calculating field UMean Reading/calculating field pMean Reading/calculating field UPrime2Mean Reading/calculating field pPrime2Mean Time = 1e-06 Courant Number mean: 0 max: 0.000871632 DILUPBiCG: Solving for Ux, Initial residual = 1, Final residual = 3.81505e-09, No Iterations 1 DILUPBiCG: Solving for Uy, Initial residual = 1, Final residual = 1.25195e-08, No Iterations 1 DILUPBiCG: Solving for Uz, Initial residual = 1, Final residual = 1.12197e-08, No Iterations 1 DICPCG: Solving for p, Initial residual = 1, Final residual = 0.0453494, No Iterations 166 time step continuity errors : sum local = 2.53027e-07, global = -7.12624e-10, cumulative = -7.12624e-10 DICPCG: Solving for p, Initial residual = 0.0592759, Final residual = 9.81774e-07, No Iterations 182 time step continuity errors : sum local = 1.52743e-09, global = -2.03866e-12, cumulative = -7.14663e-10 ExecutionTime = 5.06 s ClockTime = 5 s Calculating averages Time = 2e-06 Courant Number mean: 0.000147711 max: 0.00344423 DILUPBiCG: Solving for Ux, Initial residual = 0.347412, Final residual = 1.50109e-07, No Iterations 1 DILUPBiCG: Solving for Uy, Initial residual = 0.407471, Final residual = 3.01995e-07, No Iterations 1 DILUPBiCG: Solving for Uz, Initial residual = 0.33329, Final residual = 4.12535e-07, No Iterations 1 DICPCG: Solving for p, Initial residual = 0.0651253, Final residual = 0.00246889, No Iterations 162 time step continuity errors : sum local = 2.76872e-06, global = 2.88385e-08, cumulative = 2.81238e-08 oodles: Time = 1e-06 Courant Number mean: 0 max: 0.000871632 DILUPBiCG: Solving for Ux, Initial residual = 1, Final residual = 3.81893e-09, No Iterations 1 DILUPBiCG: Solving for Uy, Initial residual = 1, Final residual = 1.14863e-08, No Iterations 1 DILUPBiCG: Solving for Uz, Initial residual = 1, Final residual = 1.09542e-08, No Iterations 1 DICPCG: Solving for p, Initial residual = 1, Final residual = 0.045263, No Iterations 166 time step continuity errors : sum local = 2.52412e-07, global = -7.21685e-10, cumulative = -7.21685e-10 DICPCG: Solving for p, Initial residual = 0.0592747, Final residual = 9.81467e-07, No Iterations 182 time step continuity errors : sum local = 1.52615e-09, global = -2.03287e-12, cumulative = -7.23718e-10 ExecutionTime = 5.16 s ClockTime = 6 s Calculating averages Time = 2e-06 Courant Number mean: 0.000147626 max: 0.00344243 DILUPBiCG: Solving for Ux, Initial residual = 0.347412, Final residual = 1.49969e-07, No Iterations 1 DILUPBiCG: Solving for Uy, Initial residual = 0.407459, Final residual = 3.01704e-07, No Iterations 1 DILUPBiCG: Solving for Uz, Initial residual = 0.33329, Final residual = 4.12142e-07, No Iterations 1 DICPCG: Solving for p, Initial residual = 0.0651229, Final residual = 0.0024665, No Iterations 162 time step continuity errors : sum local = 2.76459e-06, global = 2.8777e-08, cumulative = 2.80532e-08 DICPCG: Solving for p, Initial residual = 0.137205, Final residual = 8.74102e-07, No Iterations 184 time step continuity errors : sum local = 5.32549e-10, global = 1.23002e-12, cumulative = 2.80545e-08 ExecutionTime = 8.61 s ClockTime = 9 s Ps: In fact I have tried to make everything is the same, but I don't know how the difference comes out. Do you have some idea about it? Thanks! Xinguang Cui |

Maybe I'm completely blind, but I could not see any difference. I mean there are some minor number difference, but ...
what are you BC? any turbulence forcing, or is there deterministic inlet, which gives always the same numbers to crunch? do you run the code parallel? good luck matej |

Thanks for your reply!
You are right, but it should be equal each other.In fact, BC is the same. The inlet condition is also sameI didn't run it in the parallel way. |

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