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#1 |
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New Member
Denis
Join Date: Jul 2011
Posts: 8
Rep Power: 16 ![]() |
Hi,
i'm trying to simulate the flow over a symmetric airfoil and computing the lift and drag coefficients. The Reynolds Number is 1e6 and i'm using the Spalart Allmaras turbulance modell. The angle of attack is 0 Here is the function to compute the coefficients: Code:
functions
{
forces
{
type forceCoeffs;
functionObjectLibs ( "libforces.so" );
outputControl timeStep;
outputInterval 1;
patches
(
Finne-Wall
);
pName p;
UName U;
log true;
rhoName rhoInf;
rhoInf 1;
CofR ( 0 0 0 );
liftDir (0 1 0);
dragDir (1 0 0);
pitchAxis ( 0 0 0 );
magUInf 22.22; // [m/s]
lRef 0.11; // [m]
Aref 0.00036385; // [m^2]
![]() Code:
SIMPLE solution converged in 319 iterations
forceCoeffs output:
Cd = 789148
Cl = -12015.9
Cm = 0
![]() Denis |
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#2 |
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Senior Member
Dave
Join Date: Jul 2010
Posts: 100
Rep Power: 17 ![]() |
Denis,
Your Aref and LRef are likely the reason you are getting such huge lift and drag coefficients. It is not unusual for a very small lift coefficient at 0 degrees (your lift is 65 times smaller than the drag) due to not quite perfect symmetry of the mesh surface. It is pretty difficult to get it exactly 0 with most meshers. Regards, Dave |
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#3 |
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New Member
Denis
Join Date: Jul 2011
Posts: 8
Rep Power: 16 ![]() |
Hi Dave,
thank you for your reply! Ok I understand that the lift-coefficient has not to be exactly zero. The main problem is the extreme high value. I attached a picture of the model. It looks like a NACA airfoil, but it is actually a fin. So I expected a lift coefficients between 0 and 4. So do you think that this is a "phyiscal" solution? Denis |
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#4 |
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Senior Member
Dave
Join Date: Jul 2010
Posts: 100
Rep Power: 17 ![]() |
Denis,
As I said in my prior post, I think the issue is your Aref. You could manually calculate the coefficients from your force output: "type forces" rather than "type forcecoeff" to confirm that your simulation is producing physically the right results. Dave |
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