CFD Online Logo CFD Online URL
www.cfd-online.com
[Sponsors]
Home > Forums > Software User Forums > OpenFOAM

Negative absolute pressure in rhoPorousMRFSimpleFoam

Register Blogs Members List Search Today's Posts Mark Forums Read

Like Tree4Likes

Reply
 
LinkBack Thread Tools Search this Thread Display Modes
Old   January 2, 2013, 13:55
Default Negative absolute pressure in rhoPorousMRFSimpleFoam
  #1
Senior Member
 
Join Date: Nov 2009
Location: Michigan
Posts: 135
Rep Power: 16
doubtsincfd is on a distinguished road
Hi,

I am trying to solve a simple problem of compressible flow through a 2D rectangular duct with a porous zone in between.

The domain is described in the attached pdf

I ran 150 iterations and I am getting negative absolute pressure in the domain, which is non-physical. I am monitoring pressure at inlet. The 0 constant and system folders are in the attached tar file.

run the script "./runIt". Observe the values of inlet pressure in log file.

How can absolute pressure go negative at all? What is going wrong in such a simple problem?

Thank you!
Attached Files
File Type: pdf domain.pdf (4.4 KB, 64 views)
File Type: gz openfoam.tar.gz (3.4 KB, 35 views)
doubtsincfd is offline   Reply With Quote

Old   January 4, 2013, 06:14
Post
  #2
Senior Member
 
T. Chourushi
Join Date: Jul 2009
Posts: 321
Blog Entries: 1
Rep Power: 17
Tushar@cfd is on a distinguished road
Hello,

It seems the solver is having problem with the boundary condition. In your case, why don't you put the BC for the pressure as;
internalField uniform 0;
outlet
{
type fixedValue;
value uniform 0;
}

Since, at the inlet boundary of your problem case you are defining the Velocity(U).

Also, if you want to use the same BC which you have mentioned in your case, then try changing the BC for velocity(U) too.
Tushar@cfd is offline   Reply With Quote

Old   January 4, 2013, 08:16
Default
  #3
Senior Member
 
Join Date: Nov 2009
Location: Michigan
Posts: 135
Rep Power: 16
doubtsincfd is on a distinguished road
Thanks, Tushar. The solution diverges in the first iteration itself when I put zero on outlet and internalField. It gives a floating point exception.
doubtsincfd is offline   Reply With Quote

Old   January 4, 2013, 22:58
Post
  #4
Senior Member
 
T. Chourushi
Join Date: Jul 2009
Posts: 321
Blog Entries: 1
Rep Power: 17
Tushar@cfd is on a distinguished road
Hello friend,

I rechecked your case, Have you changed the "controlDict" file??

Since, I am not an expert but, it seems the function that you might have added in it, could be responsible for the divergence of pressure.

Do, run the solver without the function and recheck the solution.
Tushar@cfd is offline   Reply With Quote

Old   January 7, 2013, 13:42
Default
  #5
Senior Member
 
Join Date: Nov 2009
Location: Michigan
Posts: 135
Rep Power: 16
doubtsincfd is on a distinguished road
Yes I have changed the controlDict file. But as per my understanding, the additional piece of code I have written is only for post processing purpose.

Removing that piece of code did not affect the solution.
doubtsincfd is offline   Reply With Quote

Old   January 9, 2013, 01:38
Thumbs up Hello friend,
  #6
Senior Member
 
T. Chourushi
Join Date: Jul 2009
Posts: 321
Blog Entries: 1
Rep Power: 17
Tushar@cfd is on a distinguished road
How you are defining "porosityWall" in your case? I think the problem lies somewhere with "porosityWall" you might have mistaken some parameters.
You need to check those with the available case models.
I wish this will solve your problem.

-----
Best regards,
Tushar
Tushar@cfd is offline   Reply With Quote

Old   January 9, 2013, 06:51
Default
  #7
Super Moderator
 
niklas's Avatar
 
Niklas Nordin
Join Date: Mar 2009
Location: Stockholm, Sweden
Posts: 693
Rep Power: 29
niklas will become famous soon enoughniklas will become famous soon enough
you have a massflow as inlet bc and you are running a 2D case,
so my question is then if the value of the massflow is specified in kg/s/m or in kg/s
and if the width of the channel is 1 meter or just 'thin' because that will matter.

remember that the area of the inlet will be the actual area used when calculating the inlet velocity
doubtsincfd likes this.
niklas is offline   Reply With Quote

Old   January 9, 2013, 13:36
Default
  #8
Senior Member
 
Join Date: Nov 2009
Location: Michigan
Posts: 135
Rep Power: 16
doubtsincfd is on a distinguished road
Thanks, Niklas. You are absolutely right. I wanted to simulate 1 meter depth, but the depth in blockMesh I gave was 10mm. I was not aware of the fact that the actual area of the inlet will be used by OpenFOAM for a 2D case.

Now I have increased the depth to 1 meter and the mass flow rate I have entered is in kg/s.

Actually I am trying to simulate a canonical problem for a bigger 3D problem that I am trying to solve. My original problem is same (compressible+porous+high flow rates but subsonic flow with Ma < 0.4), but it is 3D. Unfortunately I am not allowed to share the data of that problem.

I have increased the mass flow rate to 0.5 kg/s. Upto 0.5 kg/s, there is no negative absolute pressure. But as I increase the flow rate, the negative pressure problem starts becoming more and more prominent.

For 0.5 kg/s the solution stabilizes, and I get a convergence. But for higher flow rates there is instability, and in some cases it causes the solution to blow up.

I am not able to understand this negative absolute pressure, and the instability at the start of the solution. I simulated the same problem in Fluent, and the solution is smooth. The OpenFOAM results and the Fluent results are with 1% difference.

I am attaching the updated files for simulation. Script to run is "runIt.sh". Also, I am attaching plots of the convergence history.
Attached Images
File Type: jpg residuals.jpg (98.5 KB, 51 views)
Attached Files
File Type: gz openfoam.tar.gz (3.6 KB, 14 views)
doubtsincfd is offline   Reply With Quote

Old   January 9, 2013, 14:23
Default
  #9
Super Moderator
 
niklas's Avatar
 
Niklas Nordin
Join Date: Mar 2009
Location: Stockholm, Sweden
Posts: 693
Rep Power: 29
niklas will become famous soon enoughniklas will become famous soon enough
how does these settings work
Attached Files
File Type: gz p.gz (442 Bytes, 56 views)
File Type: gz U.gz (468 Bytes, 35 views)
File Type: gz fvSolution.gz (725 Bytes, 46 views)
doubtsincfd and woodwick like this.
niklas is offline   Reply With Quote

Old   January 9, 2013, 14:53
Default
  #10
Senior Member
 
Join Date: Nov 2009
Location: Michigan
Posts: 135
Rep Power: 16
doubtsincfd is on a distinguished road
Thanks for the settings.

The damping for pressure is amazing. Attached jpeg file shows residuals for first few iterations.

I will try these setting for my main problem.

I would like to know the reason behind the change in settings.

Also, the problem of negative pressure at the start of iterations still exists (though eventually it disappears). Though this does not have effect on final solution since it is a steady state problem, I am not able to understand how the equation of state is getting satisfied with negative absolute pressure. The domain does not show negative absolute temperature anywhere.
Attached Images
File Type: jpg residualsNew.jpg (94.2 KB, 62 views)
doubtsincfd is offline   Reply With Quote

Old   January 10, 2013, 09:29
Default
  #11
Senior Member
 
Join Date: Nov 2009
Location: Michigan
Posts: 135
Rep Power: 16
doubtsincfd is on a distinguished road
Hi Niklas,

I have an important question about the boundary condition at outlet. For pressure, you have suggested totalPressure boundary condition at outlet with the value of p0 =101325 Pa. But when I post-process, it shows static pressure = 101325 Pa at the outlet. So is OpenFOAM really fixing the static pressure at outlet instead of total pressure? Why is this happening despite of the value specified for total pressure?
doubtsincfd is offline   Reply With Quote

Old   January 10, 2013, 09:46
Default
  #12
Senior Member
 
Join Date: Nov 2009
Location: Michigan
Posts: 135
Rep Power: 16
doubtsincfd is on a distinguished road
So I looked at the totalPressureFvPatchScalarField.C and the code is:

operator==(p0p - 0.5*(1.0 - pos(phip))*magSqr(Up));

My reading of the equation:
pos(1) function returns 1, since flow is leaving the domain. This make the term - 0.5*(1.0 - pos(phip))*magSqr(Up) go to zero and so static pressure value is equal to total pressure value.

But, I am not able to understand what p0p does and what the = operator does. Can someone please check my explanation and help me understand p0p and = operator?
doubtsincfd is offline   Reply With Quote

Old   January 10, 2013, 09:49
Default
  #13
Super Moderator
 
niklas's Avatar
 
Niklas Nordin
Join Date: Mar 2009
Location: Stockholm, Sweden
Posts: 693
Rep Power: 29
niklas will become famous soon enoughniklas will become famous soon enough
Im going to make a wild guess here and assume that your massflow is too low to really make a difference.

What happens if you increase the massflow?
niklas is offline   Reply With Quote

Old   January 10, 2013, 09:52
Default
  #14
Super Moderator
 
niklas's Avatar
 
Niklas Nordin
Join Date: Mar 2009
Location: Stockholm, Sweden
Posts: 693
Rep Power: 29
niklas will become famous soon enoughniklas will become famous soon enough
and/or your convergence criteria for pressure is too large
niklas is offline   Reply With Quote

Old   January 10, 2013, 11:32
Default
  #15
Senior Member
 
Join Date: Nov 2009
Location: Michigan
Posts: 135
Rep Power: 16
doubtsincfd is on a distinguished road
Thank you, Niklas.

If I have understood you correctly, do you mean to say that for higher mass flow rates and/or tighter convergence criterion for pressure, the static pressure might deviate from the desired value?

For the current flow conditions, inlet mass flow rate = 2kg/s
Velocity at outlet = 160 m/s
Static pressure at outlet = 101325 Pa
Total pressure at outlet (cal from ptot utility) = 106703 Pa
Maximum mach number = 0.285

For higher flow rates (> 4kg/s) and with current settings, the solution diverges after 2 iterations
doubtsincfd is offline   Reply With Quote

Old   January 11, 2013, 03:09
Default
  #16
Super Moderator
 
niklas's Avatar
 
Niklas Nordin
Join Date: Mar 2009
Location: Stockholm, Sweden
Posts: 693
Rep Power: 29
niklas will become famous soon enoughniklas will become famous soon enough
Quote:
Originally Posted by doubtsincfd View Post
Thank you, Niklas.

If I have understood you correctly, do you mean to say that for higher mass flow rates and/or tighter convergence criterion for pressure, the static pressure might deviate from the desired value?

For the current flow conditions, inlet mass flow rate = 2kg/s
Velocity at outlet = 160 m/s
Static pressure at outlet = 101325 Pa
Total pressure at outlet (cal from ptot utility) = 106703 Pa
Maximum mach number = 0.285

For higher flow rates (> 4kg/s) and with current settings, the solution diverges after 2 iterations
Yes, thats what I think.
I cant explain why the static pressure is 101325, other than that you havent converged the pressure
enough.

About the divergence, try to reduce the under-relaxation for rho even more and observe...
What that low under-relaxation I would run more than 2000 iteration just to see if there is
something changing slowly after that.
niklas is offline   Reply With Quote

Old   January 11, 2013, 09:47
Default
  #17
Senior Member
 
Join Date: Nov 2009
Location: Michigan
Posts: 135
Rep Power: 16
doubtsincfd is on a distinguished road
Quote:
Yes, thats what I think.
I cant explain why the static pressure is 101325, other than that you havent converged the pressure
enough.
For the same simulation (2kg/s), I ran the simulation for 6000 iterations, and here are my observations:

1. Residuals < 1e-06
2. Inlet pressure value remains constant for >2000 iterations
3. Outlet pressure value rock solid at 101325 for all iterations suggesting that the solver is not solving for static pressure at outlet

Quote:
About the divergence, try to reduce the under-relaxation for rho even more and observe...
What that low under-relaxation I would run more than 2000 iteration just to see if there is
something changing slowly after that.
For higher flow rate [> 5kg/s], I reduced the k-epsilon relaxation to 0.2 and the simulation ran without divergence. URFs for p and rho were the same
doubtsincfd is offline   Reply With Quote

Old   January 13, 2013, 12:59
Default
  #18
Super Moderator
 
niklas's Avatar
 
Niklas Nordin
Join Date: Mar 2009
Location: Stockholm, Sweden
Posts: 693
Rep Power: 29
niklas will become famous soon enoughniklas will become famous soon enough
Quote:
Originally Posted by doubtsincfd View Post
For the same simulation (2kg/s), I ran the simulation for 6000 iterations, and here are my observations:

1. Residuals < 1e-06
2. Inlet pressure value remains constant for >2000 iterations
3. Outlet pressure value rock solid at 101325 for all iterations suggesting that the solver is not solving for static pressure at outlet



For higher flow rate [> 5kg/s], I reduced the k-epsilon relaxation to 0.2 and the simulation ran without divergence. URFs for p and rho were the same
ok, btw how do you look at the pressure at the outlet?
niklas is offline   Reply With Quote

Old   January 13, 2013, 16:01
Default
  #19
Member
 
Join Date: Jun 2012
Posts: 76
Rep Power: 13
maHein is on a distinguished road
Quote:
Originally Posted by doubtsincfd View Post
So I looked at the totalPressureFvPatchScalarField.C and the code is:

operator==(p0p - 0.5*(1.0 - pos(phip))*magSqr(Up));

My reading of the equation:
pos(1) function returns 1, since flow is leaving the domain. This make the term - 0.5*(1.0 - pos(phip))*magSqr(Up) go to zero and so static pressure value is equal to total pressure value.

But, I am not able to understand what p0p does and what the = operator does. Can someone please check my explanation and help me understand p0p and = operator?
Your explanation is correct! If the flow enters the domain, p0 is interpreted as total pressure (for this reason the dynamic pressure is subtracted from p0 to get the static pressure). Is the flow leaving the domain, p0 is used as static pressure. That's why you will always get a static pressure of 101325 Pa at the outlet.

The =-operator just defines what happens when the boundary conditions are updated. So in this case, the static pressure at the outlet is calculated using the above equation.
maHein is offline   Reply With Quote

Old   January 14, 2013, 08:10
Default
  #20
Super Moderator
 
niklas's Avatar
 
Niklas Nordin
Join Date: Mar 2009
Location: Stockholm, Sweden
Posts: 693
Rep Power: 29
niklas will become famous soon enoughniklas will become famous soon enough
Hmm, I've never thought about this but its correct.

Using total pressure as outlet bc is most likely unstable considering that you can
reduce the pressure and increase the velocity, while maintaining the value of p0.

use fixedValue instead.
immortality likes this.
niklas is offline   Reply With Quote

Reply

Thread Tools Search this Thread
Search this Thread:

Advanced Search
Display Modes

Posting Rules
You may not post new threads
You may not post replies
You may not post attachments
You may not edit your posts

BB code is On
Smilies are On
[IMG] code is On
HTML code is Off
Trackbacks are Off
Pingbacks are On
Refbacks are On


Similar Threads
Thread Thread Starter Forum Replies Last Post
Negative Absolute Pressure mike FLUENT 8 December 18, 2014 03:50
Manifold Absolute Pressure in Engine Simulations abminternet OpenFOAM 4 July 4, 2011 11:45
seeking for help about a room with negative pressure mengyue1 FLUENT 0 November 26, 2009 06:40
negative static pressure Selo melo FLUENT 5 December 18, 2006 09:30
avoiding negative absolute pressure!!! Tania FLUENT 8 March 30, 2004 18:41


All times are GMT -4. The time now is 05:37.