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#1 |
Member
Join Date: Jul 2010
Posts: 52
Rep Power: 16 ![]() |
Hi!
In kEpsilon.C, G is defiened as: Code:
volScalarField::Internal G ( this->GName(), nut.v()*(dev(twoSymm(tgradU().v())) && tgradU().v()) ); volScalarField G1= this->nut_*(dev(twoSymm(tgradU())) && tgradU()); Thanks, Mary |
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#2 |
Senior Member
René Thibault
Join Date: Dec 2019
Location: Canada
Posts: 114
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I got the same question lately. Did you get an answer for your question?
Regards, |
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#3 |
Senior Member
Mark Olesen
Join Date: Mar 2009
Location: https://olesenm.github.io/
Posts: 1,715
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#4 |
Senior Member
Mandeep Shetty
Join Date: Apr 2016
Posts: 188
Rep Power: 11 ![]() |
This is what I have understood.
The volScalarField is a typedef of GeometricField<>. So volScalarField contains an internal field a boundaryfield etc. Now, the volScalarField::Internal is the 'type' of the internal field in the volscalarField. It's defined by typedefing of Diemnsionedfield. For volScalarField the 'Internal' translates to: Code:
typedef DiamensionedField<Scalar, volMesh> Internal; Code:
volScalarField::Internal G ( this->GName(), nut.v()*(dev(twoSymm(tgradU().v())) && tgradU().v()) ); Code:
DimensionedField<scalar, volField> G ( this->GName(), nut.v()*(dev(twoSymm(tgradU().v())) && tgradU().v()) ); |
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kepsilon, volscalarfield |
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