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[General] Vectors in z-direction

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Old   September 5, 2012, 05:41
Default Vectors in z-direction
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Hey all,

just a (simple?) question. I wanna show the glyph on a slice only on the z-velocity component. If I am using the filter glyph I get the vector of the mag(U). Is it possible to show only the glyph in z-direction? If yes (and I think that is not a problem) how can I manage it.

Thanks in advance
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Old   September 8, 2012, 15:27
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Hi Tobi,

I'm a bit late to answer you, but one of the answers is rather simple: use the Calculator filter!

Use it to create a new vector, based on the original one, but which you only copy the Z data Or you could even use it to point to X or Y

Best regards,
Bruno
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Old   September 10, 2012, 11:52
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Quote:
Originally Posted by wyldckat View Post
Hi Tobi,

I'm a bit late to answer you, but one of the answers is rather simple: use the Calculator filter!

Use it to create a new vector, based on the original one, but which you only copy the Z data Or you could even use it to point to X or Y

Best regards,
Bruno

Hi Bruno,

I used the calculator filter - but how can I create a Vectorfield ?
Well I ll have a look at it later again.

Tobi
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Old   September 14, 2012, 06:29
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Tobi,

If your have a vector field named e.g. "velocity", try "velocity_Z*kHat" as the calculator expression, where the field name with a _Z (or _X or _Y for x- and y-axes) appended denotes a scalar field of the z-axis component of the vector field and kHat is a z-directional unit vector (0 0 1). And glyph the "Result" vector field.

Also, when you check the result by making a comparison with a glyph representation of the original vector field, don't forget to set the scale factors of the glyph filters (for the Z-component field and for the original field) to an identical value so that they have the same visual magnification.

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Old   September 15, 2012, 12:59
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Hi all,

I forget something and mixed up some wrong details.

I have a plane with the normal to z.
So I wanna have the Glyph on that plane with the x and y components. the z - component should be zero

Well one way I found out is to plot the glyph as normal and set the view direction normal to the surface so you can not see the z-components couse that is parallel to the direction of view and so you do not realize that.

After it I switch to 2D - glyph and it looks very nice.

But is there a other solution? More like the way Takuya goes?

Hope now its clear?

Tobi
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Old   September 15, 2012, 13:31
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It is so trivial if you get the full idea of my previous post that I'd leave you to find the solution by yourself. Just look for the x- and y-directional unit vector names (similar to kHat for the z direction) from the calculator panel.

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Old   September 15, 2012, 16:00
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Oh yes - it is

Thanks a lot.
Never realized the operators "kHat, jHat, iHat" since 2 years
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Old   September 15, 2012, 16:06
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Hey Takuya,

well a further question.
Do you know how to remove the vectors on the boundarys ? :/

Like in the picture? I tried to set the z-component to zero but it dont work?
Any suggestions?

Tobi
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File Type: jpg 2Dvectors.jpg (66.7 KB, 27 views)
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Old   September 15, 2012, 16:23
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Quote:
Originally Posted by Tobi View Post
Hey Takuya,

well a further question.
Do you know how to remove the vectors on the boundarys ? :/

Like in the picture? I tried to set the z-component to zero but it dont work?
Any suggestions?

Tobi
SOLVED ... Thanks for reading and your advice.

Tobi
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Old   July 19, 2022, 05:40
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Hello Tobi,

Would you mind sharing the screenshot of your calculator? I have an X plane and my equation looks like the attachment based on Takuya's answer.

I was thinking of using sqrt with z and y, but it doesn't work. There is no way to select the result array name from the calculator in the orientation array of the glyph filter.

Regards,
Paul
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Last edited by Paul Caicedo; July 29, 2022 at 02:43.
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