# Introduction to turbulence/Statistical analysis/Ensemble average

(Difference between revisions)
 Revision as of 22:39, 8 February 2007 (view source)Hammett (Talk | contribs)m (Fix minor error in 2cd equation.)← Older edit Revision as of 18:57, 19 February 2007 (view source)Rong (Talk | contribs) (→The mean or ensemble average)Newer edit → Line 18: Line 18: Now if all the coins are the same, it doesn't really matter whether we flip one coin $N$  times, or $N$  coins a single time. The key is that they must all be ''independent events'' - meaning the probability of achieving a head or tail in a given flip must be completely independent of what happens in all the other flips. Obviously we can't just flip one coin and count it $N$ times; these cleary would not be independent events Now if all the coins are the same, it doesn't really matter whether we flip one coin $N$  times, or $N$  coins a single time. The key is that they must all be ''independent events'' - meaning the probability of achieving a head or tail in a given flip must be completely independent of what happens in all the other flips. Obviously we can't just flip one coin and count it $N$ times; these cleary would not be independent events - Unless you had a very unusual experimental result, you probably noticed that the value of the $X_{10}$'s was also a random variable and differed from ensemble to ensemble. Also the greater the number of flips in the ensemle, thecloser you got  to $X_{N}=1/2$. Obviously the bigger $N$ , the less fluctuation there is in $X_{N}$ + Unless you had a very unusual experimental result, you probably noticed that the value of the $X_{10}$'s was also a random variable and differed from ensemble to ensemble. Also the greater the number of flips in the ensemle, the closer you got  to $X_{N}=1/2$. Obviously the bigger $N$ , the less fluctuation there is in $X_{N}$ Now imagine that we are trying to establish the nature of a random variable $x$. The $n$th ''realization'' of $x$  is denoted as $x_{n}$. The ''ensemble average'' of $x$ is denoted as $X$ (or $\left\langle x \right\rangle$ ), and ''is defined as'' Now imagine that we are trying to establish the nature of a random variable $x$. The $n$th ''realization'' of $x$  is denoted as $x_{n}$. The ''ensemble average'' of $x$ is denoted as $X$ (or $\left\langle x \right\rangle$ ), and ''is defined as'' Line 30: Line 30:
(2)
(2)
- Obviously it is impossible to obtain the ensemble average experimentally, since we can never an infinite number of independent realizations. The most we can ever obtain is the ariphmetic mean for the number of realizations we have. For this reason the arithmetic mean can also referred to as the ''estimator'' for the true mean ensemble average. + Obviously it is impossible to obtain the ensemble average experimentally, since we can never achieve an infinite number of independent realizations. The most we can ever obtain is the arithmetic mean for the number of realizations we have. For this reason the arithmetic mean can also referred to as the ''estimator'' for the true mean ensemble average. Even though the true mean (or ensemble average) is unobtainable, nonetheless, the idea is still very useful. Most importantly,we can almost always be sure the ensemble average exists, even if we can only estimate what it really is. The fact of its existence, however, does not always mean that it is easy to obtain in practice. All the theoretical deductions in this course will use this ensemble average. Obviously this will mean we have to account for these "statistical differenced" between true means and estimates when comparing our theoretical results to actual measurements or computations. Even though the true mean (or ensemble average) is unobtainable, nonetheless, the idea is still very useful. Most importantly,we can almost always be sure the ensemble average exists, even if we can only estimate what it really is. The fact of its existence, however, does not always mean that it is easy to obtain in practice. All the theoretical deductions in this course will use this ensemble average. Obviously this will mean we have to account for these "statistical differenced" between true means and estimates when comparing our theoretical results to actual measurements or computations. - In general, the $x_{n}$ couldbe realizations of any random variable. The $X$ defined by equation 2.2 representsthe ensemble average of it. The quantity $X$ is sometimes referred to as the ''expacted value '' of the random variables $x$ , or even simple its ''mean''. + In general, the $x_{n}$ could be realizations of any random variable. The $X$ defined by equation 2.2 represents the ensemble average of it. The quantity $X$ is sometimes referred to as the ''expected value '' of the random variables $x$ , or even simple its ''mean''. For example, the velocity vector at a given point in space and time $x^{\rightarrow},t$ , in a given turbulent flow can be considered to be a random variable, say $u_{i} \left( x^{\rightarrow},t \right)$. If there were a large number of identical experiments so that the  $u^{\left( n \right)}_{i} \left( x^{\rightarrow},t \right)$ in each of them were identically distributed, then the ensemble average of $u^{\left( n \right)}_{i} \left( x^{\rightarrow},t \right)$ would be given by For example, the velocity vector at a given point in space and time $x^{\rightarrow},t$ , in a given turbulent flow can be considered to be a random variable, say $u_{i} \left( x^{\rightarrow},t \right)$. If there were a large number of identical experiments so that the  $u^{\left( n \right)}_{i} \left( x^{\rightarrow},t \right)$ in each of them were identically distributed, then the ensemble average of $u^{\left( n \right)}_{i} \left( x^{\rightarrow},t \right)$ would be given by Line 45: Line 45:
(2)
(2)
- Note that this ensemble average, $U_{i} \left( x^{\rightarrow},t \right)$ , will , in general, vary with independent variables $x^{\rightarrow}$ and $t$. It will be seen later, that under certain conditions the ensemble average is the same as the average wich would be generated by averaging in time. Even when a time average is not meaningful, however, the ensemble average can still be defined; e.g., as in non-stationary or periodic flow. Only ensemble averages will be used in the development of the turbulence equations here unless otherwise stated. + Note that this ensemble average, $U_{i} \left( x^{\rightarrow},t \right)$ , will , in general, vary with independent variables $x^{\rightarrow}$ and $t$. It will be seen later, that under certain conditions the ensemble average is the same as the average which would be generated by averaging in time. Even when a time average is not meaningful, however, the ensemble average can still be defined; e.g., as in non-stationary or periodic flow. Only ensemble averages will be used in the development of the turbulence equations here unless otherwise stated. == Fluctuations about the mean == == Fluctuations about the mean ==

# The ensemble and Ensemble Average

## The mean or ensemble average

The concept of an ensebmble average is based upon the existence of independent statistical event. For example, consider a number of inviduals who are simultaneously flipping unbiased coins. If a value of one is assigned to a head and the value of zero to a tail, then the average of the numbers generated is defined as

 $X_{N}=\frac{1}{N} \sum{x_{n}}$ (2)

where our $n$ th flip is denoted as $x_{n}$ and $N$ is the total number of flips.

Now if all the coins are the same, it doesn't really matter whether we flip one coin $N$ times, or $N$ coins a single time. The key is that they must all be independent events - meaning the probability of achieving a head or tail in a given flip must be completely independent of what happens in all the other flips. Obviously we can't just flip one coin and count it $N$ times; these cleary would not be independent events

Unless you had a very unusual experimental result, you probably noticed that the value of the $X_{10}$'s was also a random variable and differed from ensemble to ensemble. Also the greater the number of flips in the ensemle, the closer you got to $X_{N}=1/2$. Obviously the bigger $N$ , the less fluctuation there is in $X_{N}$

Now imagine that we are trying to establish the nature of a random variable $x$. The $n$th realization of $x$ is denoted as $x_{n}$. The ensemble average of $x$ is denoted as $X$ (or $\left\langle x \right\rangle$ ), and is defined as

 $X = \left\langle x \right\rangle \equiv \lim_{N \rightarrow \infty} \frac{1}{N} \sum^{N}_{n=1} x_{n}$ (2)

Obviously it is impossible to obtain the ensemble average experimentally, since we can never achieve an infinite number of independent realizations. The most we can ever obtain is the arithmetic mean for the number of realizations we have. For this reason the arithmetic mean can also referred to as the estimator for the true mean ensemble average.

Even though the true mean (or ensemble average) is unobtainable, nonetheless, the idea is still very useful. Most importantly,we can almost always be sure the ensemble average exists, even if we can only estimate what it really is. The fact of its existence, however, does not always mean that it is easy to obtain in practice. All the theoretical deductions in this course will use this ensemble average. Obviously this will mean we have to account for these "statistical differenced" between true means and estimates when comparing our theoretical results to actual measurements or computations.

In general, the $x_{n}$ could be realizations of any random variable. The $X$ defined by equation 2.2 represents the ensemble average of it. The quantity $X$ is sometimes referred to as the expected value of the random variables $x$ , or even simple its mean.

For example, the velocity vector at a given point in space and time $x^{\rightarrow},t$ , in a given turbulent flow can be considered to be a random variable, say $u_{i} \left( x^{\rightarrow},t \right)$. If there were a large number of identical experiments so that the $u^{\left( n \right)}_{i} \left( x^{\rightarrow},t \right)$ in each of them were identically distributed, then the ensemble average of $u^{\left( n \right)}_{i} \left( x^{\rightarrow},t \right)$ would be given by

 $\left\langle u_{i} \left( x^{\rightarrow} , t \right) \right\rangle = U_{i} \left( x^{\rightarrow} , t \right) \equiv \lim_{N \rightarrow \infty} \frac{1}{N} \sum^{N}_{n=1} u^{ \left( n \right) }_{i} \left( x^{\rightarrow} , t \right)$ (2)

Note that this ensemble average, $U_{i} \left( x^{\rightarrow},t \right)$ , will , in general, vary with independent variables $x^{\rightarrow}$ and $t$. It will be seen later, that under certain conditions the ensemble average is the same as the average which would be generated by averaging in time. Even when a time average is not meaningful, however, the ensemble average can still be defined; e.g., as in non-stationary or periodic flow. Only ensemble averages will be used in the development of the turbulence equations here unless otherwise stated.

It is often important to know how a random variable is distributed about the mean. For example, figure 2.1 illustrates portions of two random functions of time which have identical means, but are obviuosly members of different ensembles since the amplitudes of their fluctuations are not diswtributed the same. it is possible to distinguish between them by examining the statistical properties of the fluctuations about the mean (or simply the fluctuations) defined by:

 $X^{'}= x- X$ (2)

It is easy to see that the average of the fluctuation is zero, i.e.,

 $\left\langle x^{'} \right\rangle = 0$ (2)

On the other hand, the ensemble average of the square of the fluctuation is not zero. In fact, it is such an important statistical measure we give it a special name, the variance, and represent it symbolically by either $var \left[ x \right]$ or $\left\langle \left( x^{'} \right) ^{2} \right\rangle$ The variance is defined as

 $var \left[ x \right] \equiv \left\langle \left( x^{'} \right) ^{2} \right\rangle = \left\langle \left[ x - X \right]^{2} \right\rangle$ (2)
 $= \lim_{N\rightarrow \infty} \frac{1}{N} \sum^{N}_{n=1} \left[ x_{n} - X \right]^{2}$ (2)

Note that the variance, like the ensemble average itself, can never really be measured, since it would require an infinite number of members of the ensemble.

It is straightforward to show from eqaution 2.2 that the variance in equation 2.6 can be written as

 $var \left[ x \right] = \left\langle x^{2} \right\rangle - X^{2}$ (2)

Thus the variance is the second-moment minus the square of the first-moment (or mean). In this naming convention, the ensemble mean is the first moment.

The variance can also referred to as the second central moment of x. The word central implies that the mean has been subtructed off before squaring and averaging. The reasons for this will be clear below. If two random variables are identically distributed, then they must have the same mean and variance.

The variance is closely related to another statistical quantity called the stardard deviation or root mean square (rms) value of the random variable $x$ , which is denoted by the simbol, $\sigma_{x}$. Thus,

 $\sigma_{x} \equiv \left( var \left[ x \right] \right)^{1/2}$ (2)

or

 $\sigma^{2}_{x} = var \left[ x \right]$ (2)

## Higher moments

Figure 2.2 illustrates tow random variables of time which have the same mean and also the same variances, but clearly they are still quite different. It is useful, therefore, to define higher moments of the distribution to assist in distinguishing these differences.

The $m$-th moment of the random variable is defined as

 $\left\langle x^{m} \right\rangle = \lim_{N \rightarrow \infty} \frac{1}{N} \sum^{N}_{n=1} x^{m}_{n}$ (2)

It is usually more convenient to work with the central moments defined by:

 $\left\langle \left( x^{'} \right)^{m} \right\rangle = \left\langle \left( x-X \right)^{m} \right\rangle = \lim_{N \rightarrow \infty} \frac{1}{N} \sum^{N}_{n=1} \left[x_{n} - X \right]^{m}$ (2)

The central moments give direct information on the distribution of the values of the random variable about the mean. It is easy to see that the variance is the second central moment (i.e., $m=2$ ).