Sutherland law

(Difference between revisions)

Latest revision as of 17:27, 17 May 2007

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-Sutherland's law for molecular viscosity coefficient is given by
+#REDIRECT [[Sutherland's law]]
-:<math>
-\mu = \mu_{\mbox{ref}} \left( \frac{T}{T_{\mbox{ref}}} \right)^{3/2} \frac{ T_{\mbox{ref}} + T_s }{ T + T_s}
-</math>
-For air,
-* <math>T_s = 110.6 K</math>
-* <math>T_{\mbox{ref}} = 273.15 K</math>
-* <math>\mu_{\mbox{ref}} = 1.716 \times 10^{-5} kg/(m-s)</math>