CFD Online Discussion Forums - volScalarField::Internal vs. volScalarField

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volScalarField::Internal vs. volScalarField

Hi!

In kEpsilon.C, G is defiened as:

Code:

    volScalarField::Internal G

    (

        this->GName(),

        nut.v()*(dev(twoSymm(tgradU().v())) && tgradU().v())

    );

Why is it defined as "volScalarField::Internal" instead of just a simple "volScalarFiled"? And have something like this:

volScalarField G1= this->nut_*(dev(twoSymm(tgradU())) && tgradU());

Thanks,

Mary

I got the same question lately. Did you get an answer for your question?

Regards,

Quote:

Originally Posted by Tibo99 (Post 789449)

I got the same question lately. Did you get an answer for your question?

The question to ask yourself: if it were a volScalarField, which is an internal field (with dimensions) and a boundary - what would you like to calculate on the boundaries?

This is what I have understood.
The volScalarField is a typedef of GeometricField<>. So volScalarField contains an internal field a boundaryfield etc. Now, the volScalarField::Internal is the 'type' of the internal field in the volscalarField. It's defined by typedefing of Diemnsionedfield.
For volScalarField the 'Internal' translates to:

Code:

typedef DiamensionedField<Scalar, volMesh> Internal;

So, the code

Code:

    volScalarField::Internal G

    (

        this->GName(),

        nut.v()*(dev(twoSymm(tgradU().v())) && tgradU().v())

    );

Can be seen as

Code:

    DimensionedField<scalar, volField> G

    (

        this->GName(),

        nut.v()*(dev(twoSymm(tgradU().v())) && tgradU().v())

    );