Center of Pressure multiplication

ENGRTAHIR · November 19, 2014, 11:45

Dear All
I am solving external flow on a half symmetry model and want to calculate Cl, Cd, Cm, Cp( center of Pressure. My question is since model is half one have to multiply the factor of 2 with Cd, Cl, Cm. Will he also multiply the value of Cp with 2. The formula which i use for calculation of center of pressure is
CPX=((areaInt_x(X*Pressure)@car+areaInt(X*Wall Shear X)@car)) /((areaInt_x(Pressure)@car+areaInt(Wall Shear X)@car))

CPY=((areaInt_y(Y*Pressure)@car+areaInt(Y*Wall Shear Y)@car)) /((areaInt_y(Pressure)@car+areaInt(Wall Shear Y)@car))

CPZ=((areaInt_z(Z*Pressure)@car+areaInt(Z*Wall Shear Z)@car)) /((areaInt_z(Pressure)@car+areaInt(Wall Shear Z)@car))

singer1812 · November 20, 2014, 17:09

No, you dont need to do that.

But you dont need to calculate CP in the sym normal direction. That will lie right on the sym plane. If you calculate it, it will be in the body away from the sym plane becuase you dont have the other side in your model.

November 19, 2014, 11:45	Center of Pressure multiplication	#1
ENGRTAHIR Member tahir Join Date: May 2010 Posts: 35 Rep Power: 15	Dear All I am solving external flow on a half symmetry model and want to calculate Cl, Cd, Cm, Cp( center of Pressure. My question is since model is half one have to multiply the factor of 2 with Cd, Cl, Cm. Will he also multiply the value of Cp with 2. The formula which i use for calculation of center of pressure is CPX=((areaInt_x(XPressure)@car+areaInt(XWall Shear X)@car)) /((areaInt_x(Pressure)@car+areaInt(Wall Shear X)@car)) CPY=((areaInt_y(YPressure)@car+areaInt(YWall Shear Y)@car)) /((areaInt_y(Pressure)@car+areaInt(Wall Shear Y)@car)) CPZ=((areaInt_z(ZPressure)@car+areaInt(ZWall Shear Z)@car)) /((areaInt_z(Pressure)@car+areaInt(Wall Shear Z)@car))

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November 20, 2014, 17:09		#2
singer1812 Senior Member Edmund Singer P.E. Join Date: Aug 2010 Location: Minneapolis, MN Posts: 511 Rep Power: 20	No, you dont need to do that. But you dont need to calculate CP in the sym normal direction. That will lie right on the sym plane. If you calculate it, it will be in the body away from the sym plane becuase you dont have the other side in your model.