[boubou]

Hi,

There is here a copy of a run in progress, my problem is the value of my variable for the slave processor 7. Why is it different from the other slave processors ? I don't understand...

I used a User Fortran routine but the problem does not seem to come from this.

Thanks !

================================================== ====================
OUTER LOOP ITERATION = 9 CPU SECONDS = 1.013E+03
Start function USER_DEBIT
TEMP = 8.9183311E+01
End function USER_DEBIT
----------------------------------------------------------------------
| Equation | Rate | RMS Res | Max Res | Linear Solution |
+----------------------+------+---------+---------+------------------+
| Wallscale | 0.70 | 6.6E-07 | 4.6E-05 | 44.6 2.5E-01 ok|
+----------------------+------+---------+---------+------------------+
| U-Mom | 0.78 | 1.8E-03 | 7.9E-02 | 2.3E-02 OK|
| V-Mom | 0.68 | 1.7E-03 | 3.2E-02 | 1.6E-02 OK|
| W-Mom | 0.62 | 8.8E-04 | 2.3E-02 | 2.3E-02 OK|
| P-Mass | 0.74 | 5.9E-05 | 3.1E-03 | 19.7 8.0E-02 OK|
+----------------------+------+---------+---------+------------------+
| K-TurbKE | 0.90 | 5.7E-03 | 2.6E-01 | 6.3 2.8E-03 OK|
| O-TurbFreq | 0.70 | 7.5E-04 | 3.3E-02 | 8.2 6.8E-04 OK|
+----------------------+------+---------+---------+------------------+
Slave: 2 Start function USER_DEBIT
Slave: 2 TEMP = 8.9183311E+01
Slave: 2 End function USER_DEBIT
Slave: 3 Start function USER_DEBIT
Slave: 3 TEMP = 8.9183311E+01
Slave: 3 End function USER_DEBIT
Slave: 4 Start function USER_DEBIT
Slave: 4 TEMP = 8.9183311E+01
Slave: 4 End function USER_DEBIT
Slave: 5 Start function USER_DEBIT
Slave: 5 TEMP = 8.9183311E+01
Slave: 5 End function USER_DEBIT
Slave: 6 Start function USER_DEBIT
Slave: 6 TEMP = 8.9183311E+01
Slave: 6 End function USER_DEBIT
Slave: 7 Start function USER_DEBIT
Slave: 7 TEMP = 8.9551163E+01
Slave: 7 End function USER_DEBIT
Slave: 8 Start function USER_DEBIT
Slave: 8 TEMP = 8.9183311E+01
Slave: 8 End function USER_DEBIT
Slave: 7 Start function USER_DEBIT
Slave: 7 TEMP = 8.9628439E+01
Slave: 7 End function USER_DEBIT

[Opaque]

Your code (user fortran) is writing some value of temperature from each partition, and you are asking why they are different. Is that value the temperature at ? say: node, boundary, global maximum, average etc ?

Describing what your goal is, how you are trying to achieve it, and the current symptoms could help others in the forum to pitch in; otherwise, it is nearly impossible to contribute.

[boubou]

Yes I realize that I have not been very explicit.

TEMP is not a temperature, it is a variable that I set. This variable depends on the mass flow rate which is the inlet boundary condition of my problem.

The goal of TEMP is to calculate at each iteration a criteria that measures the convergence.

What I don't understand is the execution of the parallel run. On my other calculations the structure was :
Slave 2 : ...
Slave 3 : ...
Slave 4 : ...
Slave 5 : ...
Slave 6 : ...
Slave 7 : ...
Slave 8 : ...

Now it is :
Slave 2 : ...
Slave 3 : ...
Slave 4 : ...
Slave 5 : ...
Slave 6 : ...
Slave 7 : ...
Slave 8 : ...
Slave 7 : ...

Why there is an other execution of slave 7 at the end ?

[Opaque]

Let us review,

Describing what your goal is,

The goal of TEMP is to calculate at each iteration a criteria that measures the convergence.

how you are trying to achieve it,

????

the current symptoms

What I don't understand is the execution of the parallel run. On my other calculations the structure was :
Slave 2 : ...
Slave 3 : ...
Slave 4 : ...
Slave 5 : ...
Slave 6 : ...
Slave 7 : ...
Slave 8 : ...

Now it is :
Slave 2 : ...
Slave 3 : ...
Slave 4 : ...
Slave 5 : ...
Slave 6 : ...
Slave 7 : ...
Slave 8 : ...
Slave 7 : ...

You are still missing important information for anybody to help you.. How are you approaching your solution via the custom code ? UserCEL, or JunctionBox ? Do you understand how ANSYS CFX breaks down the mesh on the specific locale the user code is called ?

In any case, you seem to be assuming a specific parallel programming paradigm (say: one ordered call per XXX) when writing your custom code (User Fortran); however, the software is free to call your custom code "on demand" and it is up to you to handle such events.

Imagine the software could call the custom code on the inlet for a sub-group of element faces at a time? For example, lets say you have 100 faces on the inlet, and the code breaks them down in 3 groups of 30 and 1 group of 10 for a serial run. Then , the custom code for the inlet will be called 3 times. In a parallel run, the situation is more complex because some partitions will have faces on the inlet and some will not. Have you accounted for such situations ?

[boubou]

Thanks for your reply Opaque !

You are still missing important information for anybody to help you.. How are you approaching your solution via the custom code ?

Sorry, I understand but I don't have permission to explain what I do... However I admit that I that I didn't understand how a parallel run works and your example is very clear, I will try to see in details my partitions.