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Axysimmetric cases compare to planar case with symmetry boundary condition

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Old   June 7, 2011, 07:40
Default Axysimmetric cases compare to planar case with symmetry boundary condition
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hafiidz jaafar
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Hi guys,

I am trying to run an 2D axisymmetric underexpanded jet fire using fluent. However, to simpify the case we use the pseudo diameter approach and focus just on the visible length of the flame ( the shock waves are being excluded).

I created my mesh using Gambit. setting it up to be an axisymmetric case. However, when I exported it to Fluent, I can't run it with the BC that i have set in Gambit as I can't initialize it. But when I changed it to planar cases and the axis to symmetry, it can be initialized.

I hope someone can point me what's the difference between these two settings and how can I overcome it.

Thank you.
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Old   June 8, 2011, 13:40
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Casey
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A few questions:

what version of fluent are you using?
Is it a cracked version or do you have a license?
When you make your mesh in gambit to you export it as a 2D mesh?

Are you going into define-models (i think that is the way, my fluent is down for a little while) and setting the solver to axisymmetric?
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Old   June 8, 2011, 17:46
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xrs333
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Hi, jaafar,
For axisymmetric model, it is necessary that the axis must be X axis and the grid above X axis.
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Old   June 9, 2011, 03:17
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hafiidz jaafar
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meangreen

I am using fluent 12 and 13. Both of them are with license. I exported it with 2d mesh as well. I have defined it in the general part in FLUENT.

xrs333

I see. i will try that. Anyway, is there any differences of result between axisymmetric model and setting a planar model with symmetry boundary condition.

thank you for the reply guys.
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Old   June 9, 2011, 10:26
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Hi, Jaafar,
They are absolutely different.
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Old   June 14, 2011, 06:29
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hafiidz jaafar
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Thank you for your reply.
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