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September 2, 2008, 21:39
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mixed difference
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A second-order centreal mixed difference scheme is given as
du/dxdy|i,j = (u_i+1,j+1 + u_i-1,j-1 - u_i-1,j+1 - u_i+1,j-1)/ (4*delta_x*delta_y) How can I treat the boundary points? (i.e. du/dxdy|0,0) Thanks Shuo |
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September 3, 2008, 01:25
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Re: mixed difference
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Biased difference scheme, forward or backward stencils
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