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December 16, 2015, 14:36 |
Three-body-collision reaction calc M
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#1 |
Super Moderator
Tobias Holzmann
Join Date: Oct 2010
Location: Tussenhausen
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Dear all,
I am searching for literature or some website where I can find how the third-body-collision partner "M" is calculated. In my book I found that M is calculated as: Code:
M = [H2] + 6.5[H2O] + 0.4[O2] + 0.4[N2] + 0.75[CO] + 1.5[CO2] + 3.0[CH4] Code:
H+O2(+M)=HO2(+M) .5580E+13 .400 .0 LOW/ .8400E+18 -.800 .0 / TROE/ .5000 .1000E-29 .1000E+31 / H2O/ 18.00/H2/ 2.50/N2/ 1.26/AR/ .80/HE/ .80/CO/ 1.20/CO2/ 2.40/
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December 16, 2015, 17:09 |
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#2 |
Super Moderator
Tobias Holzmann
Join Date: Oct 2010
Location: Tussenhausen
Posts: 2,708
Blog Entries: 6
Rep Power: 51 |
Hi,
just to be more clear. In many reactions there are these additional lines that indicate the species + factor that has to be used for the calculation of [M] but sometimes there is no line. Here I am not sure which [M] I have to use?!
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Keep foaming, Tobias Holzmann |
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