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March 11, 2010, 04:01 |
Two-Phase Continuity Equation
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#1 |
Senior Member
Claus Meister
Join Date: Aug 2009
Location: Wiesbaden, Germany
Posts: 241
Rep Power: 17 |
Hey Folks!
In VOF method the the density distribution is defined by rho:=rho1 alpha+(1-alpha) rho2. When I consider the following integral m(omega)=int_omega rho dV i obtain the mass in omega. the conservation mass states that by progessing time there is no change in mass at all, i.e.: Dm/Dt=0 I used Reynolds theorem and carried out a direct evaluation and I obtained (rho1-rho2) (dalpha/dt)+(rho1 alpha+(1-alpha) rho2) div u=0 Now the question is, is that correct conuity form for VOF method? Cheers, Claus |
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