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Old   April 7, 2015, 15:55
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Originally Posted by hwsv07 View Post
LES

I also have a quesition on the grid size on LES.

So the advantage of LES over DNS is that the grid size of LES can be larger, thus reducing computation time.

LES equations are obtained by a spatial filter of the NS equations. The filter width should be larger than Kolmogorov scale (smallest length scale in the problem). LES is then performed on the filtered NS equations. The scales which are smaller than the filter width are modelled by a Sub-Grid Scale (SGS) model, and the effects are therefore accounted in the solution.

If I understand LES correctly, filter width = grid size?

I have started off with steady RANS and moved to unsteady simulation. Now, I am confused whether LES or URANS is giving me a correct representation.

if the filter width Delta is implicitly related to the grid size h, then yes, the computational grid measure the smallest resolved scale..
However, it is possible to use an explicit filtering in LES. In such a way, the filter width can be as larger as you want, for example 4 times the computational grid size or greater
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Old   April 7, 2015, 16:21
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Originally Posted by hwsv07 View Post

- I also read that RANS equations is also ensemble averaging, which is averaging over a large number of the same experiment? Why would the result be different if they are all numerical experiments (shouldn't the result be always the same)?
Let me pic up this topic.
Recently, I experimented with a Rayleigh Taylor Instability using Fluents VOF method just for fun (see the picture on the left).
As it turned out, even with an undisturbed initial solution (a perfectly flat interface) I was able to trigger the instability. It is the roundoff errors that accumulate and produce the initial disturbance.
What is even more surprising in the first place is that for example reordering the grid and running the simulation again produced an entirely different solution.
So the roundoff errors that are random to some extent are usually enough to produce different solutions for two otherwise identical DNS.
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Old   April 7, 2015, 16:41
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Quote:
Originally Posted by flotus1 View Post
Let me pic up this topic.
Recently, I experimented with a Rayleigh Taylor Instability using Fluents VOF method just for fun (see the picture on the left).
As it turned out, even with an undisturbed initial solution (a perfectly flat interface) I was able to trigger the instability. It is the roundoff errors that accumulate and produce the initial disturbance.
What is even more surprising in the first place is that for example reordering the grid and running the simulation again produced an entirely different solution.
So the roundoff errors that are random to some extent are usually enough to produce different solutions for two otherwise identical DNS.

well, this is a typical effect, even simply porting the code on a different computer o using different compliers you see different numerical transient...
However, it is really important assessing that the statistics are all equal, whatever the numerical transient is
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Old   April 7, 2015, 16:41
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if the filter width Delta is implicitly related to the grid size h, then yes, the computational grid measure the smallest resolved scale..
However, it is possible to use an explicit filtering in LES. In such a way, the filter width can be as larger as you want, for example 4 times the computational grid size or greater
thanks for the reply. To be explicit in my understanding, is there any recommended criterion on how to set the width of the filter? Must the size be for e.g., be in the inertial subrange?
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Old   April 7, 2015, 16:47
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Originally Posted by hwsv07 View Post
thanks for the reply. To be explicit in my understanding, is there any recommended criterion on how to set the width of the filter? Must the size be for e.g., be in the inertial subrange?

for implicit-based filtering, the size is determined by the grid and numerical method, you can only set exactly the grid size, not the filter width...
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Old   April 7, 2015, 16:50
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Quote:
Originally Posted by flotus1 View Post
Let me pic up this topic.
Recently, I experimented with a Rayleigh Taylor Instability using Fluents VOF method just for fun (see the picture on the left).
As it turned out, even with an undisturbed initial solution (a perfectly flat interface) I was able to trigger the instability. It is the roundoff errors that accumulate and produce the initial disturbance.
What is even more surprising in the first place is that for example reordering the grid and running the simulation again produced an entirely different solution.
So the roundoff errors that are random to some extent are usually enough to produce different solutions for two otherwise identical DNS.
were you solving for a steady solution?

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Originally Posted by FMDenaro View Post
well, this is a typical effect, even simply porting the code on a different computer o using different compliers you see different numerical transient...
However, it is really important assessing that the statistics are all equal, whatever the numerical transient is
Im rather confused. if i understood correctly, the production of different results has nothing to do with the equations to be solved (e.g. RANS, LES), but rather how the grid is structured and the precision handling of the computers on which the simulation is run.
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Old   April 7, 2015, 17:06
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in LES you compute statistics after a long-time integration is solved and several flow fields are sampled...
Difference in the statistics can be due to the grid, to the numerical model, to the SGS model, etc.
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Old   April 7, 2015, 18:25
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to compute transient (unsteady) solutions, how should one choose between URANS or LES? kindly explain in simple terms.
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Old   April 7, 2015, 20:47
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Quote:
Originally Posted by hwsv07 View Post
to compute transient (unsteady) solutions, how should one choose between URANS or LES? kindly explain in simple terms.
I have the same question. For one specific problem, I can use the same grid sizes for URANS and LES. Which one to choose, URANS or LES?
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Old   April 8, 2015, 03:30
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URANS and LES provides solutions that have different meaning! the URANS is statistically averaged, the LES is filtered in space but not in time (if you do not use specific time-filtering apporach).

Using URANS o LES depends on the problem and on what you want to compute...but LES requires more refined grids than URANS
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Old   April 8, 2015, 03:55
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Originally Posted by FMDenaro View Post
URANS and LES provides solutions that have different meaning! the URANS is statistically averaged, the LES is filtered in space but not in time (if you do not use specific time-filtering apporach).

Using URANS o LES depends on the problem and on what you want to compute...but LES requires more refined grids than URANS
Thanks for your reply.

Quote:
URANS and LES provides solutions that have different meaning! the URANS is statistically averaged, the LES is filtered in space but not in time (if you do not use specific time-filtering apporach)."
From the definition, they indeed have the different meaning. But the final form of the averaged equations (URANS) and filtered equation (LES) are nearly identical, except that the form of the sub-grid parameterization. To me it just like one method with two different parameterization methods.

Quote:
Using URANS o LES depends on the problem and on what you want to compute...but LES requires more refined grids than URANS
I've read this text many times, but the answer I want to know is how to decide to choose RANS or LES for one specific problem, but not "it depends". I'm also curious to know, for one specific LES study, if I do a URANS study with the same grid size, what' wrong?

Thank you.
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Old   April 8, 2015, 04:12
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the mathematical equations looks similar but they differ for the expression of the unresolved terms. They take into account different unresolved tensors.

URANS can be used when an external unsteady force is present, for example the compression/expansion flow in cylinder due to the piston motion.

comparing LES and URANS on the same computational grid can give very different results for many reasons...
just as example, if you use a very very refined grid, LES solution will automatically tend to DNS, URANS does not.
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Old   April 8, 2015, 05:29
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Originally Posted by FMDenaro View Post
the mathematical equations looks similar but they differ for the expression of the unresolved terms. They take into account different unresolved tensors.

URANS can be used when an external unsteady force is present, for example the compression/expansion flow in cylinder due to the piston motion.

comparing LES and URANS on the same computational grid can give very different results for many reasons...
just as example, if you use a very very refined grid, LES solution will automatically tend to DNS, URANS does not.
Without regarding computation time, can i say, one should always trust LES to give a better result?

Can you help me understand how fine the grid should be for LES cases?
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Old   April 8, 2015, 07:03
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Without regarding computation time, can i say, one should always trust LES to give a better result?

Can you help me understand how fine the grid should be for LES cases?

the answer is...it depends!
you can find very bad LES simulations... (too coarse grid, to dissipative model, etc)

the guideline for a LES grid is to solve wall boundary by using at least 3-4 cells within y+<=1.
Unbounded flow regions can be meshed by grid sizes dx+,dy+,dz+ = O(10)-O(20)
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Old   April 8, 2015, 07:39
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thanks. im new to CFD and appreciate the reply.

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the answer is...it depends!
you can find very bad LES simulations... (too coarse grid, to dissipative model, etc)
why would LES be too dissipative? i thought LES resolves all large scales, and only small scales are modelled - unless you mean that the SGS model are also too dissipative in the first place.

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the guideline for a LES grid is to solve wall boundary by using at least 3-4 cells within y+<=1.
Unbounded flow regions can be meshed by grid sizes dx+,dy+,dz+ = O(10)-O(20)
refining the mesh to achieve a 3-4 cells representation of y+ = 1 would require a very fine mesh.

if im interested only in wake structures, which are far away from walls, do I have to resolve my grid to such a resolution?
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Old   April 8, 2015, 08:41
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Some SGS models are purely dissipative in nature (e.g., the Smagorinsky) and could strongly affect the energy transfer of large resolved scales.

Furthermore, if you have vortical structures in wakes but that interacts with a wall (that is are generated by stress or are dissipated within the B.L.) you need to have a refined grid at wall. Some wall model exists in LES that allows to apply special B.C. at y+>1 but the full success is debatable.
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Old   April 9, 2015, 15:02
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Some SGS models are purely dissipative in nature (e.g., the Smagorinsky) and could strongly affect the energy transfer of large resolved scales.

Furthermore, if you have vortical structures in wakes but that interacts with a wall (that is are generated by stress or are dissipated within the B.L.) you need to have a refined grid at wall. Some wall model exists in LES that allows to apply special B.C. at y+>1 but the full success is debatable.
i have been rereading this statement many times.

since the size of the filter is implicity implied by the grid size, does it always mean that the mesh density of a LES case is always higher than URANS?
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Old   April 9, 2015, 15:10
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yes, generally LES grid is more computational extensive even for the fact that URANS could be used (depending on the problem) in 2D.
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Old   April 9, 2015, 16:26
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yes, generally LES grid is more computational extensive even for the fact that URANS could be used (depending on the problem) in 2D.
in a few posts back, u mentioned that

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URANS can be used when an external unsteady force is present, for example the compression/expansion flow in cylinder due to the piston motion.
can you explain how you judged that URANS can also be suitable (i assume LES is just as suitable in the quoted case ; please correct me if wrong).

in my current problem, im only interested in the wake (and my domain is set so large that it will not interact with the walls). For LES, must I still be bothered with refining the grid then? Will URANS suffice?
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Old   April 9, 2015, 17:25
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your question is not so well-posed ...
let me explain better, you have a flow problem to solve and you have to choose the suitable tool.
Now you said to be interested in wake..that does not say nothing useful to me...what parameter you need from your solution? It is the type of information you need in the wake that can drive to the correct tool.
Therefore, if the wake is generated my a mixing of two or more corrent, you have a sort of evolving mixing layer that requires fine grid and correct time accuracy. You need to analyze special frequency analysis? that drives to LES as the time scales are solved directly.

Consider my suggestion, ask yourself what you really need in your problem and step-by-step decide the correct tool.

Some reading of a book such http://www.cambridge.org/us/academic...urbulent-flows

cna be useful
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