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July 20, 2011, 12:35 
kEqn in kEpsilon.C

#1 
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fisch
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Hello,
i try to understand the equations for the kepsilon turb model. the equation for k is: tmp<fvScalarMatrix> kEqn ( fvm::ddt(k_) + fvm::div(phi_, k_)  fvm::Sp(fvc::div(phi_), k_)  fvm::laplacian(DkEff(), k_) == G  fvm::Sp(epsilon_/k_, k_) ); i understand all terms except the second and the third... As far as i get it these terms should represent div(k*phi) But how can + fvm::div(phi_, k_)  fvm::Sp(fvc::div(phi_), k_) == div(k*phi) ??? Thanks for any advice, rupert 

July 21, 2011, 05:09 

#2 
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Bernhard
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Be aware, that the term in the original equation is equal to
which is equal to These are the two terms you see in the kEqn. For a converged solution, the second term vanishes (continuity), but it is numerically favorable to keep it while solving the equation. By the way: origin of fvm::Sp(fvc::div(phi_), epsilon_) in kepsilon Eqn? 

July 22, 2011, 01:21 

#3 
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fisch
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Thanks Bernhard,
the mentioned origin term (U * grad(k)) was wrong in some of my books ( it was just div(k * U). I had right now a look into the "Turbulent Flows" book of Pope and you're right with the origin of the term... So the question is answered. Thanks again. rupert 

July 22, 2011, 02:53 

#4 
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Bernhard
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No, it was nog wrong in the other books, the second term is just zero, since the div(U) = 0


July 22, 2011, 04:30 

#5 
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fisch
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thats right.
thanks 

July 22, 2011, 09:24 

#6 
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fisch
Join Date: Feb 2010
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I had a look on this kepsilon calculation and wanted to figure out what happens if wall functions are active.
Maybe you know answers to the three following questions, too!? If i use kqR and epsilon wall functions in my calculations he "updates" this G and forces the values for epsilon on the wall region. He's not touching k, right? And as far as i get it this "modified" G is used in the k equation at the wall region, too, right? Is there any documentation about OpenFOAM which formulas were used from the theory (like original equations for kEqn, the wall functions, and so on)??? thanks a lot rupert 

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