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January 24, 2013, 07:51
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#20 |
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Member
Gregor Olenik
Join Date: Jun 2009
Location: http://greole.github.io/
Posts: 89
Rep Power: 16  |
Hi H
take Eq. 5 and divide it by k^(1/2) and you get: - c_B*rho*k*Delta^(-1) = 2/3 rho*k^(1/2)*trace(D)-2*c_k*Delta*D^2 now substitute k by k=K^2, this yields - c_B*rho*K^2*Delta^(-1) = 2/3 rho*K*trace(D)-2*c_k*Delta*D^2 solve for K and resubstitute K=sqrt(k). That is at least my opinion of whats happening 
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