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October 4, 2011, 08:21 |
Fieldfunction du/dy - du/dx
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#1 |
Senior Member
Join Date: Dec 2010
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Hi guys,
I have got a little problem. I want to set up a field function where velocity gradients are included: e.g: du/dx -> CCM Code: grad($$Velocity[0]). I think this is for du/dx right, where u is the first component of the velocity vector. How does this work for du/dy or du/dz?? Thanks for help |
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October 4, 2011, 11:34 |
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#2 |
Senior Member
Join Date: Apr 2009
Posts: 154
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Check out the help file:
Using Tools > Using Field Functions > Field Function Programming Reference > Vector Functions, Miscellaneous Functions
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October 5, 2011, 19:10 |
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#3 |
Senior Member
Join Date: Mar 2009
Location: Austin, TX
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"grad($$Velocity[0])" will get you a vector field function consisting of (du/dx, du/dy, du/dz). If you just want du/dx, then you need to do "grad($$Velocity[0])[0]"
To be clear... du/dx = grad($$Velocity[0])[0] du/dy = grad($$Velocity[0])[1] dv/dx = grad($$Velocity[1])[0] dv/dy = grad($$Velocity[1])[1] dw/dx = grad($$Velocity[2])[0] etc... |
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October 6, 2011, 02:25 |
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#4 |
Senior Member
Join Date: Dec 2010
Posts: 135
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Ah Kyle, thank u! :-) This is it what I was looking for....
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