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Boundary Condition for Driven Cavity problem

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Old   December 25, 2000, 19:48
Default Boundary Condition for Driven Cavity problem
  #1
dado
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Hello, I am using a Finite difference method for solving Incompressible N-S equations on a staggered grid in a driven cavity flow (SIMPLE with pressure correction method with Mat Lab). Does anyone have an idea about the boundary condition for pressure and velocity? I have velocity grid outside of domain and I was trying to implemented velocity as v(1,= -v(2, (or u) for points outside a domain (there is a wall between thus points with non slip condition), pressure on the boundary was the same as a pressure in a next point in, p(1,=p(2, (with dp/dx|_w = 0 and dp/dy|_w = 0 for y-direction). But I have not a god result. My program work well for channel flow (couetteflow). Can anyone help me with boundary condition?
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Old   December 26, 2000, 00:18
Default Re: Boundary Condition for Driven Cavity problem
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Ghanshyam Singh
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You better fix the pressure at the center of the cavity along with the BCs you are using at present. I wonder, how did you get good answer for channel flow? Will you pl. tell me the details.

GS
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Old   December 26, 2000, 06:53
Default Re: Boundary Condition for Driven Cavity problem
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senthil
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hi i agree with Mr.singh.If that does'nt work try fixing the pressure some where on the lid( > than the initial assumption for pressure) by
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Old   December 26, 2000, 10:58
Default Re: Boundary Condition for Driven Cavity problem
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JunseokKim
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what about the boundary condition for the moving lid?

some people put the boundary condition like this

u(i,j_max +1) = 2.0*(moving lid velocity) - u(i,j_max)

for i=1, ... , i_max.

This is from the book "Numerical Simulaton in Fluid Dynamics"

by Michael Griebel
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Old   January 11, 2001, 00:12
Default Re: Boundary Condition for Driven Cavity problem
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Enggar Sadtopo
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Hello Dado,

In non-slip BCs velocities on the wall = 0 (u=0, v=0) except at 1 side (top). For pressure correction step you have a Neumann BC on the wall ( dp/dn=0 ). A pressure datum p=0 is specified at the middle of the bottom wall.

I'll tell u that singularities will develop where the boundary contour isn't smooth.

Enggar
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Old   January 15, 2001, 04:53
Default Re: Boundary Condition for Driven Cavity problem
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Pavan Sharma
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Sir, i m doing my project on pressure correction techniques followed by Suhas Patankar. I m working on Simple, Simpler & Simplec algorithm applied on the problem "LID DRIVEN CAVITY". I need the codes in C or FORTRAN language. If u can give, it will oblige me.

sincerely urs Pavan Sharma Final Year, IIT Guwahati

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