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September 28, 2009, 20:51 |
isothermal B.C.
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#1 |
New Member
shuo
Join Date: Apr 2009
Posts: 17
Rep Power: 17 |
I have a question regarding the implementation of isothermal no slip wall boundary condition. I am using ghost points at (i+1) to generate a wall at i + 1/2.
u_i = - u_i+1 v_i = - v_i+1 rho_i = rho_i+1 P_i = P_i+1 T_i = ? Cheers S. |
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October 2, 2009, 11:31 |
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#2 |
New Member
preetam
Join Date: Oct 2009
Posts: 1
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I guess it will be a constant and specify a value for your temperature.
For example you can use Ti=60F |
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October 2, 2009, 13:03 |
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#3 |
Super Moderator
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If you follow your logic for other variables, you should choose T_(i+1) so that
(T_i + T_(i+1))/2 = Twall You cannot of course specify density, pressure and temperature. You must choose only two of them, perhaps, pressure and temperature. |
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