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January 20, 2012, 11:24
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Kurganov-Tadmor scheme
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New Member
Nereus
Join Date: Sep 2011
Posts: 18
Rep Power: 14  |
I'm a little confused regarding the implementation of the Kurganov-Tadmoor scheme, specifically with regards to the local maximum propogation speed.
![a_{i\pm\frac{1}{2}}(t)=\max\left[\rho\left(\frac{\partial F(u_i(t))}{\partial u}\right),\rho\left(\frac{\partial F(u_{\pm i}(t))}{\partial u}\right)\right]](/Forums/vbLatex/img/40b215529859e20170cfeb49385a7d76-1.gif "a_{i\pm\frac{1}{2}}(t)=\max\left[\rho\left(\frac{\partial F(u_i(t))}{\partial u}\right),\rho\left(\frac{\partial F(u_{\pm i}(t))}{\partial u}\right)\right]") Now, say my flux is simply a 1D advective  . Then,  , right? So, does the right hand side of the equation above simply boil down to  , because that seems far too simple? Or, have I misunderstood the mathematics?
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