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January 20, 2012, 11:24 |
Kurganov-Tadmor scheme
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#1 |
New Member
Nereus
Join Date: Sep 2011
Posts: 18
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I'm a little confused regarding the implementation of the Kurganov-Tadmoor scheme, specifically with regards to the local maximum propogation speed.
Now, say my flux is simply a 1D advective . Then, , right? So, does the right hand side of the equation above simply boil down to , because that seems far too simple? Or, have I misunderstood the mathematics? |
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January 21, 2012, 08:09 |
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#2 |
Senior Member
duri
Join Date: May 2010
Posts: 245
Rep Power: 16 |
The derivative represents eigen value of jacobian A. If you are solving 1D buger's equation in max() term is correct.
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