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December 14, 2016, 08:37 |
I really need your help!!
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#1 |
Member
Jianhua.Liu
Join Date: Jul 2016
Posts: 30
Rep Power: 9 |
Hello everyone! I try to do a research of conjugate heat transfer, and I use MARKⅡturbine blade for that. Now I have the coordinates of blade and blade's holes(like picture 1 and picture 2), but when I put into ICEM, It is like picture3,how can I do that they can like picture 4? How should I do to transform for that? I really need your help! Thanks in adcance!
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December 18, 2016, 11:40 |
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#2 |
Member
Utkan Caliskan
Join Date: Aug 2014
Posts: 42
Rep Power: 11 |
Hi,
I can help you with that. Utkan |
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December 18, 2016, 19:58 |
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#3 |
Member
Jianhua.Liu
Join Date: Jul 2016
Posts: 30
Rep Power: 9 |
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December 19, 2016, 10:57 |
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#4 |
Member
Jianhua.Liu
Join Date: Jul 2016
Posts: 30
Rep Power: 9 |
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December 20, 2016, 09:10 |
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#5 |
New Member
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December 20, 2016, 11:03 |
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#6 | |
Member
Jianhua.Liu
Join Date: Jul 2016
Posts: 30
Rep Power: 9 |
Quote:
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December 20, 2016, 11:44 |
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#7 |
New Member
Join Date: Jul 2016
Posts: 9
Rep Power: 9 |
If you know the angle between picture 3 and picture 4, you can do a rotation on all of the data points for the geometry to manually rotate it BEFORE importing into ICEM. That to me is the quickest way and can be done easily in excel, MATLAB, python, etc.
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December 21, 2016, 06:56 |
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#8 | |
Member
Jianhua.Liu
Join Date: Jul 2016
Posts: 30
Rep Power: 9 |
Quote:
Thank you for your reply! I have tried to do a ratation on holes coordinates in Excel before I ask for help, but I failed, the following is what I have done. Just like picture 1, I know the setting angle is 63deg41min31sec, so I use the following formula to convert: x=(x1-x0)cosa-(y1-y0)sina+x0 y=(x1-x0)sina+(y1-y0)cosa+y0 where (x1,y1) is holes coordinates, (x,y) is holes coordinates after rotation, (x0,y0) I am not sure how to choose, I use the point (3.434, 6.909) in picture1. It is wrong with my formula? Point datas are from this article 《analytical and experimental evaluation of the heat transfer distribution over the surfaces of turbine vanes》page 11-16. Can you help me for that? I'm quite new..... |
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December 21, 2016, 09:24 |
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#9 | |
New Member
Join Date: Jul 2016
Posts: 9
Rep Power: 9 |
Quote:
I think in your equation, (x0,y0) is the point of rotation (if it's not the origin). sources: https://www.siggraph.org/education/m...ran/2drota.htm https://en.wikipedia.org/wiki/Rotation_(mathematics) |
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