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Velocity-inlet boundary condition for flow exit |
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March 15, 2019, 02:05 |
Velocity-inlet boundary condition for flow exit
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#1 |
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For an incompressible steady state problem with density modeled through Boussinesq approximation, Is it okay to use boundary conditions such as “Mass flow inlet” for flow entry and “Velocity-inlet” (with a negative value to specify that flow exits the domain) for flow exit. By using such an approach, if we manage to achieve mass conservation, then will it be okay to change the usual practice of setting boundary conditions such as “Velocity inlet” for flow entry and “pressure outlet” with gauge pressure set to zero for flow exit. Kindly provide me your valuable insights.
[/QUOTE] : Sometimes a velocity inlet boundary is used where flow exits the physical domain. This approach might be used, for example, when the flow rate through one exit of the domain is known or is to be imposed on the model. In such cases you must ensure that overall continuity is maintained in the domain. In the pressure-based solver, when flow exits the domain through a velocity inlet boundary FLUENT uses the boundary condition value for the velocity component normal to the exit flow area. It does not use any other boundary conditions that you have input. Instead, all flow conditions except the normal velocity component are assumed to be those of the upstream cell Last edited by Manu4CFD; March 15, 2019 at 11:55. |
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March 15, 2019, 15:19 |
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#2 |
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Lucky
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Use the outlet velocity only if you specifically need/want to. That is, if you actually want an exit velocity profile to be a specific shape and value then by all means do it. But if you don't have this reason, do not play around with it.
The usual practice of using a pressure outlet is the usual practice for good reason. You need to give BC's for velocity and pressure. When you fix the velocity, you apply the zero gradient condition on pressure... Not only do you fix the outlet velocity, you also allow weird things to happen on pressure. Imagine you are solving the heat equation and the only boundary conditions is no heat flux at the boundaries. Well that allows the temperature field inside to be almost anything.... In truly incompressible flows this is okay because that's what happens in incompressible flows. But you are using a compressible solver... |
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March 16, 2019, 00:17 |
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#3 | |
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In my case, I am dealing with an incompressible fluid flow and I know the inlet mass flow rate. There is a heat source in my domain and I am using boussinesq approximation for density. I presume that in order to achieve the mass conservation, the amount of air that comes in to the domain should go out of the domain through the outlet. So, i just calculated the outlet velocity based on the outlet area to get the same mass flow rate out of the domain, as that got in to the domain through the inlet. So, under such a scenario, is the approach to use "mass-flow-inlet" as inlet condition and "velocity-inlet" as outlet condition for an incompressible fluid flow justifiable? I have attached a simple figure to depict my physics for your reference. |
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March 16, 2019, 00:26 |
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#4 | |
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If the velocity is fixed doesn't it mean that the pressure is also fixed. Say, if my outlet velocity is -0.2m/s (negative sign indicates flow exits the domain) and operating pressure is 101325Pa, doesn't it mean that air is flowing out of the domain with a velocity of 0.2m/s at 1atm? |
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March 17, 2019, 09:35 |
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#5 | |
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Lucky
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So no you don't need a velocity outlet. Your idea that mass flow is conserved is a constraint (not a boundary condition) and it will be satisfied since you are solving a continuity equation. Saying that the velocity is fixed doesn't say anything about pressure. As a corollary, saying the velocity is fixed doesn't say anything about temperature. Do the right thing. Use a pressure outlet. For incompressible flows, pressure doesn't even matter anyway. Or, there's also an outflow boundary condition you can use that is even more appropriate. |
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March 22, 2019, 03:30 |
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#6 | |
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As rightly mentioned by you, for an incompressible flow the density change with respect to pressure and temperature is negligible. Hence, the constant density approximation. Since there is a heat source in my simulation, I have used the boussinesq approximation to consider the buoyant forces. In my study, there is a room with four inlets and four outlets. I need to split the total inlet mass flow rate equally among the four outlets. Which means, say if I have 1 kg/s of total inlet mass flow rate into the domain at 16 Degree Celsius, then through each outlet the mass flow rate going out of the domain should be 0.25kg/s at 24 Degree Celsius. if i apply either of pressure outlet / outflow condition, such a constraint cannot be placed. Hence, I am specifying a velocity-inlet condition with a negative value. In this particular scenario, isn't it justifiable? |
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March 23, 2019, 00:28 |
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#7 |
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Lucky
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There is a flow split outlet boundary condition for when you want a particular % of the flow to go through a particular outlet. Surprise! There is a boundary condition that does exactly what you want that isn't fixing the velocity!
Again, you don't need a velocity outlet! Again, there are situations where you would want to use a velocity inlet at an outlet and fix all the properties at the outlet. Believe me, I have done this before! But I did it because I wanted to ignore physics and fix all the properties at the outlet. I didn't use a velocity outlet because I wanted to conserve mass and didn't know what to do. And how do you know the flow at the outlet is a uniform velocity and uniform 24 degrees Celsius? You don't. If you did, you wouldn't be solving a transport equation to solve for the velocity and temperature. Honestly think about this. You are also imposing a uniform velocity profile. What makes you think the velocity should be uniform there? For any given inlet mass flow rate. There are an infinite number of velocity profiles at the outlet that all give the same mass flow rate. What makes you think your uniform velocity of 0.2 m/s is the correct one? hmmm???? Can you prove that to me? The answer is the velocity profile of the outlet depends on what happens inside the domain. For example, there might be an elephant inside! |
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March 23, 2019, 06:05 |
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#8 | ||
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Quote:
Lol. |
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