mirroring about a non-symmetry plane

Shamoon Jamshed · December 14, 2020, 09:23

Hello friends,

does any one know how to create mirroring about a plane other than symmetry. One way i did this is that i had two planes, one with z-x plane and i named it symmetry and the other plane was rotated about 45 deg than x-z plane. I named it symm-2 and then deinfed in Fluent as symmetry too. So, my question is that Fluent does not mirror about this second plane. Can i define the plane using the button "Define Plane" option, how? What equation should i put in there?
Please help.

Regards,

SJ

AlexanderZ · December 14, 2020, 23:04

Quote:

Originally Posted by Shamoon Jamshed

So, my question is that Fluent does not mirror about this second planeJ

why do you think it doesn't?
once you've defined any plane as symmetry (boundary condition) fluent will apply symmetry conditions

Shamoon Jamshed · December 15, 2020, 07:13

There is no doubt that Fluent does mirroring, problem is that , true mirroring will be obtained if the symmetry is aligned with x-y , y-z or z-x planes. If the plane is other than these principal planes then you must specify equation and that is where I am stuck, I dont know the equation of the plane rotated 45 degree from z-x plane.

Shamoon Jamshed · December 16, 2020, 09:13

any idea fellas?

pakk · December 16, 2020, 12:19

Finding the equation for that plane is basic mathematics. If you really have no idea how to do that, you should not be doing CFD.

Sorry if I sound harsh. But come on... It's not hard.

Shamoon Jamshed · December 16, 2020, 12:26

I think the basic reason for coming to this platform was to take help, if you had to humiliate like this, may be you should not be on this platform. I can do mathematics but this was to save time. After all, who solves navier stokes equations on paper by doingg, BASIC MATHEMATICS and not doing CFD?

pakk · December 16, 2020, 13:15

My goal is not to humiliate. My goal is to make you try harder.

You can find the equation for the y-plane. What is it?

Now use the same logic for the zx-plane.
Just do it. If you fail, show where.

If you don't show any work for such a problem, I'll not help. If you show that you tried, I will

December 14, 2020, 09:23	mirroring about a non-symmetry plane	#1
Shamoon Jamshed Senior Member Shamoon Jamshed Join Date: Apr 2009 Location: Karachi Posts: 377 Rep Power: 18	Hello friends, does any one know how to create mirroring about a plane other than symmetry. One way i did this is that i had two planes, one with z-x plane and i named it symmetry and the other plane was rotated about 45 deg than x-z plane. I named it symm-2 and then deinfed in Fluent as symmetry too. So, my question is that Fluent does not mirror about this second plane. Can i define the plane using the button "Define Plane" option, how? What equation should i put in there? Please help. Regards, SJ

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December 15, 2020, 07:13		#3
Shamoon Jamshed Senior Member Shamoon Jamshed Join Date: Apr 2009 Location: Karachi Posts: 377 Rep Power: 18	There is no doubt that Fluent does mirroring, problem is that , true mirroring will be obtained if the symmetry is aligned with x-y , y-z or z-x planes. If the plane is other than these principal planes then you must specify equation and that is where I am stuck, I dont know the equation of the plane rotated 45 degree from z-x plane.

December 16, 2020, 09:13		#4
Shamoon Jamshed Senior Member Shamoon Jamshed Join Date: Apr 2009 Location: Karachi Posts: 377 Rep Power: 18	any idea fellas?

December 16, 2020, 12:19		#5
pakk Senior Member Join Date: Nov 2013 Posts: 1,965 Rep Power: 26	Finding the equation for that plane is basic mathematics. If you really have no idea how to do that, you should not be doing CFD. Sorry if I sound harsh. But come on... It's not hard.

December 16, 2020, 12:26		#6
Shamoon Jamshed Senior Member Shamoon Jamshed Join Date: Apr 2009 Location: Karachi Posts: 377 Rep Power: 18	I think the basic reason for coming to this platform was to take help, if you had to humiliate like this, may be you should not be on this platform. I can do mathematics but this was to save time. After all, who solves navier stokes equations on paper by doingg, BASIC MATHEMATICS and not doing CFD?

December 16, 2020, 13:15		#7
pakk Senior Member Join Date: Nov 2013 Posts: 1,965 Rep Power: 26	My goal is not to humiliate. My goal is to make you try harder. You can find the equation for the y-plane. What is it? Now use the same logic for the zx-plane. Just do it. If you fail, show where. If you don't show any work for such a problem, I'll not help. If you show that you tried, I will