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Viscous dissipation and isenthalpic expansion |
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August 13, 2020, 17:43 |
Viscous dissipation and isenthalpic expansion
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Member
Raphael
Join Date: Nov 2012
Posts: 68
Rep Power: 13 |
This isnt really a CFD question persay, but people here tend to be very knowledgeable, so I am asking my question anyway.
I am a bit confused about viscous dissipation. It seems to me that viscous dissipation is essentially the same thing as pumping power, such that if I pump 1 m3/s of air at 1 kPa, it takes 1 kW. To get 1 kPa pressure drop, I need a lot of friction, and that friction will cause viscous dissipation, which will result in 1 kW of heating i.e. ~0.8 K temperature rise in the air. However, for an ideal gas, enthalpy is only a function of temperature. If I expand the air through a valve instead, thermodynamics tells me the temperature wont have changed. Thanks in advance |
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Tags |
ideal gas, isenthalpic expansion, viscous dissipation |
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