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2nd order boundary conditions for 2nd order discretization?

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Old   December 3, 2011, 11:38
Default 2nd order boundary conditions for 2nd order discretization?
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Hi,

I am now using 2nd order time and space discretization for my NS eqns, using fractional step.

For the boundary conditions, e.g. at the north side, I'm using:

du/dy = 0. v=0.

If I just use a 1st order discretization of the above for my problem, it will be:

u(i,j) = u(i,j-1)

will it affect the overall order of my problem? Will it become overall 1st order?

Thanks
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