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February 26, 2013, 09:14 |
udf problem
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#1 |
New Member
nabizadeh
Join Date: May 2012
Location: iran
Posts: 23
Rep Power: 14 |
i wrote an udf code for my problem in fluent but it didn't run and i didn't know my mistake.this is my code it's about a reactor that some reaction occur in it. is there any one can help me:
#include "udf.h" # define R 8.314 # define KO_1 5.852e+17 # define KO_2 4.225e+15 # define KO_3 1.955e+6 # define KO_4 1.02e+15 # define E1 204000 # define E2 240100 # define E3 67130 # define E4 243900 # define K_CO1 4.02e+5 # define K_CO2 5.08e+4 # define K_CO3 6.65e-4 # define K_CO4 8.23e-5 # define K_CO5 6.12e-9 # define K_CO6 1.77e5 # define AH1 103500 # define AH2 66200 # define AH3 -38280 # define AH4 -70650 # define AH5 -82900 # define AH6 88680 DEFINE_SR_RATE(my_rate,f,t,r,mw,yi,rr) { Thread *t0 = THREAD_T0(t); cell_t c0 = F_C0(f,t); real y_ch4 = yi[0]; real y_h2o = yi[1]; real y_h2 = yi[2]; real y_co = yi[3]; real y_co2 = yi[4]; real y_n2 = yi[5]; real y_o2 = yi[6]; real K1, K2, K3, K4, T_w, TP ,Nsum , K_C1, K_C2, K_C3, K_C4, K_C5, K_C6, QR , keq2 , keq3 , keq4; y_ch4 *= 1/mw[0]; y_h2o *= 1/mw[1]; y_h2 *= 1/mw[2]; y_co *= 1/mw[3]; y_co2 *= 1/mw[4]; y_n2 *= 1/mw[5]; y_o2 *= 1/mw[6]; Nsum = y_ch4 + y_h2o + y_h2 + y_co + y_co2 + y_n2 + y_o2 ; y_ch4 *= 1/Nsum; y_h2o *= 1/Nsum; y_h2 *= 1/Nsum; y_co *= 1/Nsum; y_co2 *= 1/Nsum; y_n2 *= 1/Nsum; y_o2 *= 1/Nsum; T_w = F_T(f,t); K1 = KO_1*exp(-E1/(R*T_w)); K2 = KO_2*exp(-E2/(R*T_w)); K3 = KO_3*exp(-E3/(R*T_w)); K4 = KO_4*exp(-E4/(R*T_w)); K_C1 = K_CO1*exp((-AH1)/(R*T_w)); K_C2 = K_CO2*exp((-AH2)/(R*T_w)); K_C3 = K_CO3*exp((-AH3)/(R*T_w)); K_C4 = K_CO4*exp((-AH4)/(R*T_w)); K_C5 = K_CO5*exp((-AH5)/(R*T_w)); K_C6 = K_CO6*exp((-AH6)/(R*T_w)); TP = C_P(c0,t0)/1.0e+5; keq2 = (5.75e+12)*exp(-11476/TP); keq3 = (1.26e-2)*exp(4639/TP); keq4 = (7.24e+10)*exp(-21646/TP); QR = 1+(K_CO4*(TP*y_co))+(K_CO5*(TP*y_h2))+(K_CO1*(TP*y _ch4))+((K_CO6*(TP*y_h2o))/(TP*y_h2)); if (STREQ(r->name, "reaction-1")) { r1 = k1*(((TP*y_ch4)*pow(TP*y_o2,.5))/pow((1+(K_C1*(TP*y_ch4))+(K_CO2*pow(TP*y_o2,.5))), 2)); if(r1<min) { *rr = min; } else if (r1 > min && r1 < max) *rr = r1; else if (r1 > max){ *rr = max; } } else if (STREQ(r->name, "reaction-2")){ r2=((k2/pow(TP*y_h2,2.5))*(((TP*y_ch4)*(TP*y_h2o))-((pow(TP*y_h2,3)*(TP*y_co))/(keq2)))/(pow(QR,2)); if(r2 < min) { *rr = min; } else if (r2 > min && r2 < max) *rr = r2; else if (r2 > max){ *rr = max; } } else if (STREQ(r->name, "reaction-3")) { r3=((k3/(TP*y_h2))*(((TP*y_co)*(TP*y_h2o))-(((TP*y_h2)*(TP*y_co2))/(keq3)))/(pow(QR,2)); if(r3 < min) { *rr = min; } else if (r3 > min && r3 < max) *rr = r3; else if (r3 > max){ *rr = max; } } else if (STREQ(r->name, "reaction-4")){ r4=((k4/pow(TP*y_h2,3.5))*(((TP*y_ch4)*pow(TP*y_h2o,2))-(((pow(TP*y_h2,4))*(TP*y_co2))/(keq4)))/(pow(QR,2)); if(r4 < min) { *rr = min; } else if (r4 > min && r4 < max) *rr = r4; else if (r4 > max){ *rr = max; } } } |
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February 27, 2013, 03:38 |
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#2 |
Senior Member
SSL
Join Date: Oct 2012
Posts: 226
Rep Power: 15 |
You have defined all parameters. Recheck it.
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March 1, 2013, 01:28 |
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#3 |
New Member
nabizadeh
Join Date: May 2012
Location: iran
Posts: 23
Rep Power: 14 |
you mean that the code is correct?
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